嗨gh School Math : How to find the perimeter of a right triangle

Study concepts, example questions & explanations for High School Math

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Example Questions

Example Question #1 :How To Find The Perimeter Of A Right Triangle

What is the perimeter of a triangle with side lengths of 5, 12, and 13?

Possible Answers:

Correct answer:

Explanation:

To find the perimeter of a triangle you must add all of the side lengths together.

In this case our equation would look like

Add the numbers together to get the answer.

Example Question #441 :Geometry

Three points in the xy-coordinate system form a triangle.

The points are.

What is the perimeter of the triangle?

Possible Answers:

9 + \sqrt{71}

9 + \ sqrt {26}

9 + \sqrt{41}

Correct answer:

9 + \sqrt{41}

Explanation:

Drawing points gives sides of a right triangle of 4, 5, and an unknown hypotenuse.

Using the pythagorean theorem we find that the hypotenuse is\sqrt{41}.

Example Question #2 :How To Find The Perimeter Of A Right Triangle

找到符合的周长lowing triangle:

Screen_shot_2014-03-01_at_9.07.42_pm

Possible Answers:

Correct answer:

Explanation:

The formula for the perimeter of a right triangle is:

whereis the length of a side.

Use the formulas for a atriangle to find the length of the base. The formula for atriangle is.

Ourtriangle is:

Plugging in our values, we get:

Example Question #3 :How To Find The Perimeter Of A Right Triangle

找到符合的周长lowing right triangle:

Screen_shot_2014-03-01_at_9.09.16_pm

Possible Answers:

Correct answer:

Explanation:

The formula for the perimeter of a right triangle is:

whereis the length of a side.

Use the formulas for atriangle to find the length of the base and height. The formula for atriangle is

Ourtriangle is:

Plugging in our values, we get:

Example Question #1 :How To Find The Perimeter Of A Right Triangle

Triangle

Based on the information given above, what is the perimeter of triangle ABC?

Possible Answers:

Correct answer:

Explanation:

Triangle-solution

Consult the diagram above while reading the solution. Because of what we know about supplementary angles, we can fill in the inner values of the triangle. Angles A and B can be found by the following reductions:

A + 120 = 180; A = 60

B + 150 = 180; B = 30

Since we know A + B + C = 180 and have the values of A and B, we know:

60 + 30 + C = 180; C = 90

This gives us a 30:60:90 triangle. Now, since 17.5 is across from the 30° angle, we know that the other two sides will have to be √3 and 2 times 17.5; therefore, our perimeter will be as follows:

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