Call Now to Set Up Tutoring:

(888) 888-0446

High School Math : Basic Single-Variable Algebra

Study concepts, example questions & explanations for High School Math

Create An Account Create Tests & Flashcards

All High School Math Resources

8 Diagnostic Tests 613 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

← Previous 1 2 3 4 5 6 Next →

Example Question #1 :Solving Equations

Solve the pair of equations for x and y:

x+y=4

x-y=8

Possible Answers:

x=-6,y=-2

x=6, y=-2

x=2,y=-6

x=-2,y=6

x=-6,y=2

Correct answer:

x=6, y=-2

Explanation:

Equation 1: x+y=4

Equation 2: x-y=8

Solve equation 2 for X: x=8+y

Substitute into Equation 1: (8+y)+y=4

Solve for y: 2y=-4 , y=-2

Take the answer for y and plug it back into either original equation to find x:

x=6, y=-2

Report an Error

Example Question #2 :Solving Equations

Solve the pair of equations for x and y:

2x+y=16

y-2x=0

Possible Answers:

x=-4,y=8

x=8,y=-4

x=4,y=8

x=4,y=-8

x=8,y=4

Correct answer:

x=4,y=8

Explanation:

Equation 1: 2x+y=16

Equation 2: y-2x=0

Solve Equation 2 for y:

y=2x

Substitute into Equation 1:

2x+2x=16

4x=16

x=4

Plug x back into either original equations and solve for y:

x=4,y=8

Report an Error

Example Question #3 :Solving Equations

For which of the following functions is the result of f(-2) a positive integer?

Possible Answers:

5x^2 + 2

2x-5

2x-10

6x^3

2x^2-13

Correct answer:

5x^2 + 2

Explanation:

Simply plugging in -2 into each answer choice will determine the correct answer:

6x^3 = 6(-2)^3 = -48

2x-5=2(-2)-5=-9

2x^2-13=2(-2)^2-13=-5

5x^2 + 2 = 5(-2)^2 + 5 = 25

2x-10 = 2(-2) - 10 = -14

The key to solving this problem is to remember the order of operations and that negative numbers squared are positive, while negative numbers raised to the third power are negative.

Report an Error

Example Question #4 :Solving Equations

Given the equation x^3 -6 = 210 , what is the value of 2x + 3 ?

Possible Answers:

Correct answer:

Explanation:

When solving the equation x^3 - 6 = 210 , observe that x^3 = 216 . Taking the cube root of 216 gives 6. Thus, 2x + 3=2(6) + 3=15.

Report an Error

Example Question #5 :Solving Equations

A cardboard packing box contains footballs and baseballs. The ratio by weight of baseballs to footballs is 7 to 9. How many kilograms of footballs will there be in the box if the total weight of the box is 48 kilograms?

Possible Answers:

Correct answer:

Explanation:

In the box, there arekilograms of baseballs andkilograms of footballs. In total, there are 16x kilograms of balls. The total weight of the box is 48 kilograms, so $16x = 48\: and\: x = 3.$ Since there arekilograms of footballs, the total weight of the footballs in the box is equal to: 9(3) = 27.

Report an Error

Example Question #11 :Equations

Solve the following equation.

5(x - 5) = 5

Possible Answers:

x = 6

x = 25

x = -6

x = 1

x = -1

Correct answer:

x = 6

Explanation:

To begin solving, we use the distributive property to simplify the left side. We get: 5x - 25 = 5 . Then, adding 25 to both sides, we get: 5x = 30 . Dividing by 5, we get that x = 6 .

Report an Error

Example Question #12 :Equations

Solve the equation for.

4x + 2 = 3x - 1

Possible Answers:

No solution

x = 3

x = -1

x = -3

x = 1

Correct answer:

x = -3

Explanation:

4x + 2 = 3x - 1

Since we have variables on both sides, we first subtractfrom both sides.

This leaves us with x + 2 = -1 .

Subtracting 2 from both sides, we get x = -3 .

Report an Error

Example Question #13 :Equations

Solve for

4(3 - y) = 6y + 2

Possible Answers:

y = 1

$y = \frac{10}{7}$

$y = \frac{1}{7}$

$y = \frac{7}{5}$

y = 5

Correct answer:

y = 1

Explanation:

4(3 - y) = 6y + 2

First, use the distributive property to multiply out the left side:

12 - 4y = 6y + 2

Then, addon both sides:

12 = 10y + 2

Subtract 2 from both sides:

10 = 10y

Divide both sides by 10 to get 1 = y , or y = 1 .

Report an Error

Example Question #14 :Equations

Solve the following equation for.

2(z+3)=18

Possible Answers:

z = 7

z = 12

z = 7.5

z = 6

z = 2

Correct answer:

z = 6

Explanation:

The first step in solving this equation is to distribute the 2 through the parentheses. This gives us:

$2\cdot z + 2\cdot 3 = 18$

2z+6=18

Next, we subtract 6 from both sides, in order to get the variable alone on one side of the equation:

2z+6 - 6 =18-6

2z = 12

Finally, we divide both sides by 2 to solve for:

$\frac{2z}{2} = \frac{12}{2}$

z = 6

Report an Error

例子问题# 15:Equations

Solve the following equation for:

6x + 3 = 4x - 7

Possible Answers:

x = 2

x = -5

x = 5

x = -2

x = 1

Correct answer:

x = -5

Explanation:

The first step in solving this equation is to combine the like terms. That is, move all of the terms with anin it to one side of the equation, and all the terms without anto the other side. Let's begin with moving theterms to the left side of the equation. We do this by subtractingfrom each side:

6x + 3 - 4x = 4x - 7 - 4x

2x+3=-7

Next, we combine the terms without anon the right side. We do this by subtracting 3 from both sides:

2x+3-3 = -7-3

2x = -10

Finally, we divide both sides of the equation by 2 to solve for:

$\frac{2x}{2} = \frac{-10}{2}$

x = -5

Report an Error

← Previous 1 2 3 4 5 6 Next →

View Tutors

Mary Rose
Certified Tutor

McGill University, Bachelor in Arts, English.

View Tutors

Michaella
Certified Tutor

Southeastern Bible College, Bachelor of Education, Elementary School Teaching. Southeastern Bible College, Bachelor of Philos...

View Tutors

Benjamin
Certified Tutor

Portland State University, Bachelor of Science, Computer Science.

All High School Math Resources

8 Diagnostic Tests 613 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

Statistics Tutors in Denver,Computer Science Tutors in San Francisco-Bay Area,SAT Tutors in San Francisco-Bay Area,Physics Tutors in Los Angeles,French Tutors in Chicago,GRE Tutors in Philadelphia,MCAT Tutors in Chicago,SAT Tutors in San Diego,Algebra Tutors in Miami,SAT Tutors in Dallas Fort Worth

Popular Courses & Classes

SSAT Courses & Classes in Chicago,GMAT Courses & Classes in New York City,SSAT Courses & Classes in Seattle,LSAT Courses & Classes in Washington DC,LSAT Courses & Classes in Phoenix,ISEE Courses & Classes in Dallas Fort Worth,MCAT Courses & Classes in Miami,ACT Courses & Classes in Miami,GMAT Courses & Classes in Boston,ISEE Courses & Classes in Miami

Popular Test Prep

LSAT Test Prep in New York City,ACT Test Prep in Atlanta,SSAT Test Prep in Denver,LSAT Test Prep in Atlanta,SSAT Test Prep in Houston,GMAT Test Prep in Atlanta,ISEE Test Prep in Denver,GMAT Test Prep in Dallas Fort Worth,ISEE Test Prep in Miami,SSAT Test Prep in Miami

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

*Full legal name

Company name

*Phone number

*Email address

Address

*Address1

Address2

*City

*State

*Zipcode

*Country

Complaint Details

*URL of copyrighted work (where your original material is located)

*Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

*Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

High School Math : Basic Single-Variable Algebra

Study concepts, example questions & explanations for High School Math

All High School Math Resources

Example Questions

Example Question #1 :Solving Equations

Example Question #2 :Solving Equations

Example Question #3 :Solving Equations

Example Question #4 :Solving Equations

Example Question #5 :Solving Equations

Example Question #11 :Equations

Example Question #12 :Equations

Example Question #13 :Equations

Example Question #14 :Equations

例子问题# 15:Equations

All High School Math Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Find the Best Tutors

Email address:
Your name:
Feedback: