The easiest way to narrow down a square root from a list is to look at the last number on the squared number – in this case 4 – and compare it to the last number of the answer.

70 * 70 will equal XXX0

71 * 71 will equal XXX1

72 * 72 will equal XXX4

73 * 73 will equal XXX9

74 * 74 will equal XXX(1)6

Therefore 72 is the answer. Check by multiplying it out.

In order for the original statement to be true, theandterms must be eitherbothodd orbotheven. Looking at each of the statements individually,

I. States thatis odd, but only odd values multiplied by 3 are odd. Ifwas an even number, the result would be even. Butcan be either odd or even, depending on whatequals. Thus this statement COULD be true but does not HAVE to be true.

II. States thatis an integer, and since only even numbers are cleanly divided by 2 (odd values result in a fraction) this ensures thatis even. However,can also be odd, so this is a statement that COULD be true but does not HAVE to be true.

III. For exponents, only the base value determines whether it is even or odd - it does not indicate the value of y at all. Only even numbers raised to any power are even, thus, this ensures thatis even. Butcan be odd as well, so this statement COULD be true but does not HAVE to be true.

An example of two integers that will work violate conditions II and III isand.

, and even number.

is not an integer.

is not even.

Furthermore, any combination of 2 even integers will make the original statement true, and violate the Statement I.

First list all the integers between 20 and 80 that are squares of another integer:

5²= 25

6²= 36

7²= 49

8²= 64

In total, there are 61 integers from 20 to 80, inclusive. 61 – 4 = 57

Notice howis the greatest value. This often means thatis negative aswhenis odd andwhenis even.

Let us examine the first choice,

This can only be true of a negative value that lies between zero and one.

To solve foryou have to get all the's on one side and all the numbers on the other side.

Combine like terms, and the result is

.

Divide byon both sides to get

.

Finally take the square root of both sides to get.

This question is testing one's ability to analyze a function algebraically and recognize different but equivalent forms. Identifying properties of functions through analyzing equivalent forms is critical to this concept. Such properties that can be found through analyzing the different forms of a function include finding roots (zeros), extreme values, symmetry, and intercepts.

Knowing the standard and the concept for which it relates to, we can now do the step-by-step process to solve the problem in question.

Step 1: Recognize the general form of the function.

This is known as the difference of squares.

Step 2: Identify what is known.

Step 3: Substitute the known values into the difference of perfect squares found in step 1.

Step 4: Answer the question.

To find the positive solution set each binomial equal to zero and solve for x.

Therefore the positive solution is four.

Given the two equations, substitute the numerical value ofinto the second equation to solve for.

Substituting the numerical value forinto the equation withis as follows.

From here, distribute the three.

Now square both side of the equation.

Remember to square both terms within the parentheses. Also, recall that squaring a square root sign cancels them out.

To solve fordivide both sides by six.