We can use base ten blocks to help us solve this problem. First, we want to use base ten blocks to represent

Because we are dividingby, we need to split up ourinto groups of

As you can see, we havegroups. Thus the answer is.

We can use base ten blocks to help us solve this problem. First, we want to use base ten blocks to represent

Because we are dividingby, we need to split up ourinto groups of

We can see that we have 2 groups of 2, thus the answer is 2.

We can use base ten blocks to help us solve this problem. First, we want to use base ten blocks to represent .2

Because we are dividing .2 by .2, we need to split up our .2 into groups of .2:

We can see that we have 1 group, thus our answer is 1.

We can use base ten blocks to help us solve this problem. First, we want to use base ten blocks to represent

Because we are dividingby, we need to split up ourinto groups of:

As you can see, we havegroups; thus,

We can use base ten blocks to help us solve this problem. First, we want to use base ten blocks to represent

Because we are dividingby, we need to split up ourinto groups of:

As you can see, we havegroups; thus,

We can use base ten blocks to help us solve this problem. First, we want to use base ten blocks to represent

Because we are dividingby, we need to split up ourinto groups of

As you can see, we havegroups; thus,

The problem that you are challenged to solve is.

is the dividend, this is what is being broken up into groups.is our divisor which is the number of groups you are making. We need to splitin half to see how many are in each group.

The first step is to place your decimal above your equation in the same place. It will line up with the decimal inside of your "long-division house".

Next, we need to use or multiplication facts to determine whatcan be multiplied by to makeor get close to it without going over.is the fact that works best (is too large). We will place the numeraldirectly above thein the ones place to indicate thatgroups offit into the. We will put the product ofwhich wasunderneath thein the ones place and subtract the difference. The numbers above the "house" are our quotient or answer to the division problem.

Next, we will carry thein the tenths place down and put it next to the. We will work with the numbers as if they werewhen thinking of multiplication facts, but it should be noted this is actuallywhen you consider the decimal placement.so we place theabove the "house" in the tenths place of our quotient and subtract the. We are left withremaining so there is no remainder.

Our final answer is, which means that half ofis

The problem that you are challenged to solve is.

is the dividend, this is what is being broken up into groups.is our divisor which is the number of groups you are making. We need to splitin thirds to see how many are in each group.

The first step is to place your decimal above your equation in the same place. It will line up with the decimal inside of your "long-division house".

Next, we need to use or multiplication facts to determine whatcan be multiplied by to makeor get close to it without going over.is the fact that works best (is too large). We will place the numeraldirectly above thein the ones place to indicate thatgroups offit into the. We will put the product ofwhich wasunderneath theand subtract the difference. The numbers above the "house" are our quotient or answer to the division problem.

Next, we will carry thein the tenths place down and put it next to the. We will work with the numbers as if they werewhen thinking of multiplication facts, but it should be noted this is actuallywhen you consider the decimal placement.so we place theabove the "house" in the tenths place of our quotient and subtract the. We are left withremaining.

Finally, we carry down thefrom the hundredths place and place it next to thegiving us(orfor the purpose of our multiplication facts.)so we place theabove thein the hundredths place on top of our "house" and subtract theleaving us with a remainder of.

Our final answer is

The problem that you are challenged to solve is.

is the dividend, this is what is being broken up into groups.is our divisor which is the number of groups you are making. We need to splitin quarters to see how many are in each group.

The first step is to place your decimal above your equation in the same place. It will line up with the decimal inside of your "long-division house".

Next, we need to use or multiplication facts to determine whatcan be multiplied by to makeor get close to it without going over.is the fact that works best. We will place the numeraldirectly above thein the ones place to indicate thatgroups offit into the. We will put the product ofwhich wasunderneath theand subtract the difference. The numbers above the "house" are our quotient or answer to the division problem.

Next, we will carry thein the tenths place down and put it next to the.so we place theabove the "house" in the tenths place of our quotient and subtract the. We are left withremaining.

Finally, we carry down thefrom the hundredths place and place it next to the.so we place theabove thein the hundredths place on top of our "house" and subtract theleaving us with a remainder of.

Our final answer is

The problem that you are challenged to solve is.

is the dividend, this is what is being broken up into groups.is our divisor which is the number of groups you are making. We need to splitin half to see how many are in each group.

The first step is to place your decimal above your equation in the same place. It will line up with the decimal inside of your "long-division house".

Next, we need to use or multiplication facts to determine whatcan be multiplied by to makeor get close to it without going over.is the fact that works best. We will place the numeraldirectly above thein the ones place to indicate thatgroups offit into the. We will put the product ofwhich wasunderneath theand subtract the difference. The numbers above the "house" are our quotient or answer to the division problem.

Next, we will carry thein the tenths place down and put it next to the.so we place theabove the "house" in the tenths place of our quotient and subtract the. We are left withremaining so there is no remainder.

Our final answer is, which means that half ofis