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Test:Computer Science
Consider the following code:
import java.util.ArrayList;
public class MethodClass5 {
public static class BTNode {
public static final int PARSE_IN = 1;
public static final int PARSE_PRE = 2;
public static final int PARSE_POST = 3;
String name;
BTNode lPointer,rPointer;
public BTNode(String s) {
name = s;
lPointer = rPointer = null;
}
public void insert(String s) {
insert(this,s);
}
private static void insert(BTNode node,String s) {
int comparison = s.compareTo(node.name);
if(comparison < 0) {
if(node.lPointer != null) {
insert(node.lPointer,s);
} else {
node.lPointer = new BTNode(s);
}
} else if(comparison > 0) {
if(node.rPointer != null) {
insert(node.rPointer,s);
} else {
node.rPointer = new BTNode(s);
}
}
}
public ArrayList
return parse(this,parseOrder);
}
private static ArrayList
ArrayList
if(node == null) {
return(retVal);
}
ArrayList
ArrayList
if(parseOrder == PARSE_PRE) {
retVal.add(node.name);
retVal.addAll(leftList);
retVal.addAll(rightList);
} else if (parseOrder == PARSE_POST) {
retVal.addAll(leftList);
retVal.addAll(rightList);
retVal.add(node.name);
} else {
retVal.addAll(leftList);
retVal.add(node.name);
retVal.addAll(rightList);
}
return retVal;
}
}
public static void main(String[] args) {
String[] names = {"Thomas Aquinas","Thomas Cajetan","Thomas Prufer","Thomas the Tank Engine","Thomas the Bread-Eater"};
BTNode node = new BTNode(names[0]);
for(int i = 1; i < names.length; i++) {
node.insert(names[i]);
}
ArrayList
for(String s : traversedNames) {
System.out.println(s);
}
}
}
1. | What is the output for themainmethod above? |
Thomas Aquinas
Thomas the Tank Engine
Thomas Prufer
Thomas the Bread-Eater
Thomas Cajetan
Thomas the Bread-Eater
Thomas the Tank Engine
Thomas Prufer
Thomas Cajetan
Thomas Aquinas
Thomas the Bread-Eater
Thomas Aquinas
Thomas the Tank Engine
Thomas Prufer
Thomas Cajetan
Thomas Aquinas
Thomas Cajetan
Thomas Prufer
Thomas the Bread-Eater
Thomas the Tank Engine
Thomas the Tank Engine
Thomas Prufer
Thomas the Bread-Eater
Thomas Aquinas
Thomas Cajetan
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