We need to ensure that all the numbers share a common factor of.are divisible by. We getleftover along with thethat doesn't divide evenly with. Now that all these numbers share a common factor of, we multiply them all out including thewe divided out. We getor.

We need to ensure that all the numbers share a common factor of.are divisible by. We getleftover along with thethat doesn't divide evenly with. Next,are divisible by. We also getleftover. Then, we can divide thes out to get. Now that all these numbers share a common factor of, we multiply them all out including thewe divided out. We getor.

Let's divide the even numbers first. We will divide them by.

Next, we have twos, so let's divide them byto get. So far we have factors ofremaining from the original six integers with factors ofbeen used. Now that they have a common factor of, we multiply everything out. We getor.

If you divide a number by, you cannot have a remainder ofYou can either havein that order.

We are told thata,b, andcare integers, and that 4a= 6b= 11c. Becausea,b, andcare positive integers, this means that 4arepresents all of the multiples of 4, 6brepresents the multiples of 6, and 11crepresents the multiples of 11. Essentially, we will need to find the least common multiples (LCM) of 4, 6, and 11, so that 4a, 6b, and 11care all equal to one another.

First, let's find the LCM of 4 and 6. We can list the multiples of each, and determine the smallest multiple they have in common. The multiples of 4 and 6 are as follows:

4: 4, 8, 12, 16, 20, ...

6: 6, 12, 18, 24, 30, ...

The smallest multiple that 4 and 6 have in common is 12. Thus, the LCM of 4 and 6 is 12.

We must now find the LCM of 12 and 11, because we know that any multiple of 12 will also be a multiple of 4 and 6.

Let's list the first several multiples of 12 and 11:

12: 12, 24, 36, 48, 60, 72, 84, 96, 108, 120, 132, ...

11: 11, 22, 33, 44, 55, 66, 77, 88, 99, 110, 121, 132, ...

The LCM of 12 and 11 is 132.

Thus, the LCM of 4, 6, and 12 is 132.

Now, we need to find the values ofa,b, andc, such that 4a= 6b= 12c= 132.

4a= 132

Divide each side by 4.

a= 33

Next, let 6b= 132.

6b= 132

Divide both sides by 6.

b= 22

Finally, let 11c= 132.

11c= 132

Divide both sides by 11.

c= 12.

Thus,a= 33,b= 22, andc= 12.

We are asked to find the value ofa+b+c.

33 + 22 + 12 = 67.

The answer is 67.

年代incevis divisible by 2, 3 and 15,vmust be a multiple of 30. Any number that is divisible by both 2 and 15 must be divisible by their product, 30, since this is the least common multiple.

Out of all the answer choices,v+ 30 is the only one that equals a multiple of 30.

我们给出的信息,m / 4是10 than m/3. We set up an equation where m/4 = m/3 + 10.

We must then give the m variables a common denominator in order to solve for m. Since 3 * 4 = 12, we can use 12 as our denominator for both m variables.

m/4 = m/3 + 10 (Multiply m/4 by 3 in the numerator and denominator.)

3m/12 = m/3 + 10 (Multiply m/3 by 4 in the numerator and denominator.)

3m/12 = 4m/12 + 10 (Subtract 4m/12 on both sides.)

-m/12 = 10 (Multiply both sides by -12.)

m = -120

-120/4 = -30 and -120/3 = -40. -30 is 10 greater than -40.

The greatest common divisor ofandis 10. This means that the prime factorizations ofandmust both contain a 2 and a 5.

The greatest common divisor ofandis 9. This means that the prime factorizations ofandmust both contain two 3's.

The greatest common divisor ofandis 8. This means that the prime factorizations ofandmust both contain three 2's.

Thus:

We substitute these equalities into the given expression and simplify.

年代inceandare two-digit integers (equal toandrespectively), we must haveand. Any other factor values fororwill produce three-digit integers (or greater).

is equal to, socould be either 1 or 2.

Therefore:

or

Greatest common factor is a common factor shared by two or more numbers. Both numbers are even, so let's divide both numbers by two. We get. These are prime numbers (factors of one and itsef) in which we are done. Anytime we have two prime numbers or one prime and one composite number, we are finished. So the greatest common factor is.

Greatest common factor is a common factor shared by two or more numbers.is a multiple of, so let's dividefor both numbers. We get. We are finished as these are the basic numbers. So the greatest common factor is.