PSAT Math : How to factor a common factor out of squares
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Example Question #1 :Squaring / Square Roots / Radicals
x2= 36
Quantity A: x
Quantity B: 6
The relationship cannot be determined from the information given
The two quantities are equal
Quantity B is greater
Quantity A is greater
The relationship cannot be determined from the information given
x2= 36 -> it is important to remember that this leads to two answers.
x = 6 or x = -6.
If x = 6: A = B.
If x = -6: A < B.
Thus the relationship cannot be determined from the information given.
Example Question #62 :Exponents
According to Heron's Formula, the area of a triangle with side lengths of a, b, and c is given by the following:
where s is one-half of the triangle's perimeter.
What is the area of a triangle with side lengths of 6, 10, and 12 units?
14√2
48√77
8√14
4√14
12√5
8√14
We can use Heron's formula to find the area of the triangle. We can let a = 6, b = 10, and c = 12.
In order to find s, we need to find one half of the perimeter. The perimeter is the sum of the lengths of the sides of the triangle.
Perimeter = a + b + c = 6 + 10 + 12 = 28
In order to find s, we must multiply the perimeter by one-half, which would give us (1/2)(28), or 14.
现在我们有a, b, c和s,我们可以计算the area using Heron's formula.
Example Question #1 :New Sat Math No Calculator
Simplify the radical expression.
Look for perfect cubes within each term. This will allow us to factor out of the radical.
Simplify.
Example Question #2 :Squaring / Square Roots / Radicals
Simplify the expression.
Use the distributive property for radicals.
Multiply all terms by
Combine terms under radicals.
Look for perfect square factors under each radical.
Since both radicals are the same, we can add them.
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