Test the coordinates to find the ordered pair that makes the equation of the line true:

The first step is to find the equation of the line that the original points, D and E, are on. You have two points, so you can figure out the slope of the line by plugging the points into the equation

.

Therefore, you can get an equation in the line in point-slope form, which is

.

Plug in the answer options, and you will find that only the pointsolves the equation.

In order to solve this, try each of the answer choices in the equation:

For example, when we try (3,4), we find:

This does not work. When we try all the choices, we find that only (2,4) works:

AB = 10 ’

BC = AC – AB = 25’ – 10’ = 15’

CD = 2 * AB = 2 * 10’ = 20 ’

AD = AB + BC + CD = 10’ + 15’ + 20’ = 45’

Let P₁= (1, 4) and P₂= (5, 1)

Substitute these values into the distance formula:

The distance formula is an application of the Pythagorean Theorem: a²+ b²= c²

The answer is 10. Use the distance formula between 2 points, or draw a right triangle with legs length 6 and 8 and use the Pythagorean Theorem.

To find the distance between two points such as these, plot them on a graph.

Then, find the distance between theunits of the points, which is 12, and the distance between thepoints, which is 5. Therepresents the horizontal leg of a right triangle and therepresents the vertial leg of a right triangle. In this case, we have a 5,12,13 right triangle, but the Pythagorean Theorem can be used as well.

Let一个d一个d use the distance formula:

The distance between 2 points is found using the distance or Pythagorean Theorem. Because values are squared in the formula, distance can never be a negative value.

Each part of the problem gives you 2 out of the 3 pieces of the rate/time/distance relationship, thus allowing you to find the third (if needed) by using the equation:

The problem is otherwise an application of geometry and the distance formula. We need to find the distance between 2 points, but we need to go step-by-step to find out where the final point is. The first two steps are relatively easy to follow. He travels 30 miles north. Now he turns west and travels for 40 minutes at 40 mph. This isof an hour, so we have. Thus if we are looking at standard Cartesian coordinates (starting at the origin), we are now at the point.

We are now on the last step: 40 miles northeast. We need to decipher this into- and- coordinate changes. To do this, we think of a triangle. Because we are moving directly northeast, this is a 45 degree angle to the horizontal. We can thus imagine a 45-45-90 triangle with a hypotenuse of 40. Now using the relationships on triangles we have:

So the final step moves usup and to the right. Moving this way from the pointleaves us at:

Using the distance formula for this point from the origin gives us a distance of ~58 miles.

Now for the time. We traveled 30 miles at 40 mph. This means we traveled forhours or 45 minutes.

We then traveled 40 mph for 40 minutes. Increasing our total time traveled to 85 minutes.

Finally, we traveled 40 miles in 25 minutes, leaving our total time traveled at 110 minutes. Returning to hours, we havehours or 1.83 hours.

Our final average speed traveled is then:

The closest answer to this value is 32 mph.