一个ll Precalculus Resources
Example Questions
Example Question #1 :Find Intercepts And Asymptotes
Find the slant and vertical asymptotes for the equation
.
Vertical asymptote:; Slant asymptote:
Vertical asymptote:; Slant asymptote:
Vertical asymptote:; Slant asymptote:
Vertical asymptote:; Slant asymptote:
Vertical asymptote:; Slant asymptote:
Vertical asymptote:; Slant asymptote:
To find the vertical asymptote, just set the denominator equal to 0:
To find the slant asymptote, divide the numerator by the denominator, but ignore any remainder. You can use long division or synthetic division.
The slant asymptote is
.
Example Question #31 :Rational Functions
Find the slant asymptote for
.
This graph does not have a slant asymptote.
This graph does not have a slant asymptote.
By factoring the numerator, we see that this equation is equivalent to
.
That means that we can simplify this equation to.
That means thatisn't the slant asymptote, but the equation itself.
is definitely an asymptote, but a vertical asymptote, not a slant asymptote.
Example Question #32 :Rational Functions
Find the y-intercept of, if any.
Be careful not to confuse this equation with the linear slope-intercept form. The y-intercept of an equation is the y-value when the x-value is zero.
替代的价值into the equation.
Simplify the equation.
The y-intercept is:
Example Question #61 :Polynomial Functions
Find the horizontal asymptote of the function:
To find the horizontal asymptote, take the leading term of the numerator and the denominator and divide. In this case:
Example Question #41 :Rational Functions
Find the vertical and horizontal asymptotes of the function
Vertical Asymptotes:
Horizontal Asymptote:
Vertical Asymptotes:
Horizontal Asymptote:
Vertical Asymptotes:
Horizontal Asymptote:
Vertical Asymptotes:
Horizontal Asymptote:
Vertical Asymptotes:
Horizontal Asymptote:
The function
is already in simplified form.
To find the vertical asymptotes, we set the denominator equal toand solve for.
yields the vertical asymptotes
To find the horizontal asymptote, we examine the largest degree ofbetween the numerator and denominator
Note that
Because the largest degree ofin the numerator is less than the largest degree ofin the denominator, or
we find the horizontal symptote to be
Example Question #1 :Solving And Graphing Exponential Equations
Determine the asymptotes, if any:
Factorize both the numerator and denominator.
Notice that one of the binomials will cancel.
The domain of this equation cannot include.
The simplified equation is:
Since theterm canceled, theterm will have a hole instead of an asymptote.
Set the denominator equal to zero.
Subtract one from both sides.
There will be an asymptote at only:
The answer is:
Example Question #1 :Solving And Graphing Exponential Equations
Where is an asymptote located, if any?
Factor the numerator and denominator.
重写方程。
Notice that thewill cancel. This means that the root ofwill be a hole instead of an asymptote.
Set the denominator equal to zero and solve for x.
一个n asymptote is located at:
The answer is:
Example Question #1 :Find The Zeros Of A Function Using The Rational Zeros Theorem
Use the Rational Zero Theorem to find all potential rational zeros of the polynomial. Which of these is NOT a potential zero?
To find the potential rational zeros by using the Rational Zero Theorem, first list the factors of the leading coefficient and the constant term:
Constant 24: 1, 2, 3, 4, 6, 8, 12, 24
Leading coefficient 2: 1, 2
Now we have to divide every factor from the first list by every factor of the second:
Removing duplicates [for example,andare both equivalent to 1] gives us the following list:
The only choice not on this list is.
Example Question #2 :Integral And Rational Zeros Of Polynomial Functions
Consider the polynomial. Of the potential rational zeros provided by the Rational Zero Theorem, which can we determine to NOT be a solution?
The potential zeros must have a factor of -15 as their numerator and a factor of 6 as their denominator. This eliminatesas a possibility since 6 is not a factor of -15.
Now we need to test which of these values actually give zero when plugged into the polynomial.
First,:
Now:
Finally:
Since this one doesn't give us zero, it is not a solution of the polynomial.
Example Question #3 :Integral And Rational Zeros Of Polynomial Functions
Use Rational Zeros Theorem to find all potential rational zeros of the polynomial. Which of the following sets ONLY includes potential zeros?
To use Rational Zeros Theorem, take all factors of the constant term and all factors of the leading coefficient. That gives you:
Constant Term = 12, so Factors: 1, 2, 3, 4, 6, 12
Leading Coefficient = 3, so Factors: 1, 3
Then divide every number from the first list by every number from the second -- keeping in mind that both positive and negative values are possible. Of course, since this is a multiple-choice question you can also use process-of-elimination to get rid of any values that wouldn't be possible from such division. Note that the only prime factors you have are 2 and 3, meaning that there is no way to produce a 5 or 7. That eliminates (or at least makes very suspect) several choices, leaving the choice:
If you perform division from the two lists you should see how you can arrive at each value from this choice: dividing 12 by 3 would give you 4 (or negative 4, again as both + and - values are possible); dividing 2 by 3 would give you, and dividing 2 by 1 or 6 by 3 would give you 2. Therefore this choice only includes possible zeros.