This is a basic factorial question. A factorial is equal to the number times every positive whole number smaller than itself. In Column A, the numerator is 5 * 4 * 3 * 2 * 1 while the denominator is 3 * 2 * 1.

As you can see, the 3 * 2 * 1 can be cancelled out from both the numerator and denominator, leaving only 5 * 4.

The value for Column A is 5 * 4 = 20.

In Column B, the numerator is 6 * 5 * 4 * 3 * 2 * 1 while the denominator is 4 * 3 * 2 * 1. After simplifying, Column B gives a value of 6 * 5, or 30.

Thus, Column B is greater than Column A.

3 is the only answer that is a factor of both 24 and 42. 42/3 = 14 and 24/3 = 8. The other answers are either a factor of 24 OR 42 or neither, but not both.

The answer is 721(413 + 211) because we can pull out a common factor, or 721, from both sides of the equation.

Let's consider Quantity B first. What will the remainder be whenpis divided by 33?

4, 6 and 11 are factors ofpwhich means that 2 * 2 * 2 * 3 * 11 *nwill equalp. We can group the 3 and 11 to see that 33 will always be a factor ofpand will have no remainder. Thus Quantity B will always equal 0 no matter the value ofn.

Now consider Quantity A. Let's consider first the values forpwhen n equals 1 through 5. Whenn= 1,p= 264, and the remainder is 4/5 or 0.8.

n= 2,p= 528, and the remainder is 3/5 or 0.6.

n= 3,p= 792, and the remainder is 2/5 or 0.4.

n= 4,p= 1056, and the remainder is 1/5 or 0.2.

n= 5,p= 1320, and the remainder is 0 (because whenn= 5, 5 becomes a factor ofpand thus there is no remainder.

Because Quantity A can be equal to or greater than B, there is not enough information given to determine the relationship.

32 = 2 * 16 = 2 * 4 * 4 = 2 * 2 * 2 * 2 * 2 = 2⁵, so Quantity A = 5.

60 = 2 * 30 = 2 * 6 * 5 = 2 * 2 * 3 * 5 = 2²* 3 * 5, so Quantity B = 2.

Quantity A is greater. Even though 60 is a larger number than 32, 32 has more 2's in its prime factorization.

Because, the answer choice that has a factorization set that cancels out completely with 396 will produce an integer. Only 18 fits this qualification, since.

Do not try to count out the factors. A neat formula for finding the sum of factors of a number can be utilized by first determining the prime factorization of the number.

,

where s is the sum, a, b, and c are factors, and x, y, and z are the powers of these factors.

Then, a = 2, b = 5, x = 2, y = 2.

Then, a = 2, b = 5, x = 3, y = 2.

Now we can add our two sums.

This question is really asking, “How many factors of 4 are there in 16!”? To ascertain this, list all the even numbers and count the total number of 2s among those factors.

Respectively, 16, 14, 12, 10, 8, 6, 4, 2 have 4, 1, 2, 1, 3, 1, 2, 1 factors of 2.

The total then is 15. This means that you have a factor of 2¹⁵, which is the same as 4⁷* 2; therefore, since you are asked for the largest integer value ofn, 7 is your answer.

Any larger integer value would not allow 4ⁿto divide 16! evenly.

Since we're dealing with a product that comes out to a positive value, it could be the product of two positives or two negatives.

That being said, consider the ways we could factor:

For each of these four possible factors, there are four possible sums:

When the product of two numbers is positive, that means that either both numbers were positive, or both numbers were negative.

Now, considering the waycould be factored:

And of course the cases where both values are negative. For each of these potential factors, the sums are then

Absolute value signs are used to denote that either a sum or it's negative suffices. However, recall that we're told the two integers are distinct!

Due to this, neitheroris an acceptable answers, because both the integers would be equivalent and not distinct.