The first step will be to calculate how many total different potential rolls are possible. This is given by the product of the number of possible rolls for each of the dice: 6, 6, 20:

Next it is necessary to account for the total number of rolls that will sum up to 5. Writing them out can help, such as in the format of:

知道有6个不同的卷,和up to 5, the probability of rolling a 5 can be found by taking the number of events that satisfy this sum and dividing it by the number of total possible events:

Looking at this equation, note that since all terms in the numerator and denominator contain a, it is possible to rewrite it as follows:

or

Now the parenthetical terms must be addressed. The problem statement and answer choices give a clue that they are some sort of multiples of.

In fact, Pascal's triangle reveals that the top and bottom are the cube and square of this term respectively:

Cancelling terms, we are left with:

Examination of the valuereveals that after the sequence, the decimal repeats, and that the sequence has a length of eight values.

A longer answer would be to write the sequence out and count down the digits until thevalue was found. However, this is a time-consuming process and one that is prone to error.

Rather, notice how since the numbers repeat, it's possible to skip most of the counting:

digit:

digit:

And so on. Sinceis the closest multiple to, we can subtract the two to find the digit that matches thedigit.

So thedigit is.

The first step will be to find the reciprocal of百分比。请注意,百分之一,这应该是有限公司nverted to a decimal form:.

The reciprocal of a number is given bydivided by that number, so the reciprocal ofis given as:

Therefore:

比较,值ofandmust be determined.

We are told thatpercent ofis, so its value can be determined as follows:

Withknown, it is possible to find, sincepercent ofis:

The two quantities are equal.

To solve this problem, realize that a decimal may be placed at the very end of this integer:

Now, count how many spaces the decimal will need to move to the left to reach:

It must move a total ofspaces, so:

To solve this problem, begin with simplifying the numerator. This can be done by first finding a common denominator. For

a common denominator would be:

or

Which combines into:

But recall that this is just the numerator, and there is still ain the denominator:

So, the final answer is:

The best approach to this equation is to evaluate each of the equations and inequalities. The absolute value of –6 is 6, but the opposite of that value indicated by the “–“ is –6, which does not equal 6.

¹/₂is 0.5, while 1/8 is 0.125 so 0.5 > 0.125.

√17 has to be slightly more than the √16, which equals 4, so“>” should be “<”.

Finally, the fraction¹/₃has repeating 3s which makes it larger than³/₁₀so it is true.

To determine which quantity is greater, we must first determine the range of potential values for Quantity B. Let's call this quantity m. This is most efficiently done by dividing 4 by the highest and lowest possible values for n.

4/10 = 0.4

4/15 = 0.267

So the possible values for m are 0.267 < m < 0.4

Now let's find the value for 7/13, to make comparison easier.

7/13 = 0.538

Given this, no matter what the value ofnis, 7/13 will still be a higher proportion, so Quantity B is greater.

The GRE test now has a built-in calculator. Simply convert the fractions to decimals and compare:

Quantity A = 0.333 +0.43 + 0.2 = 0.963

Quantity B = 0.1429 + 0.5 + 0.3333 = 0.976

Thus, Quantity B is larger.