Which of the following will form a circle when graphed?

The equation of a circle follows the general formula of

Where r is the radius of the circle, and (h,k) are the coordinates of the center of the circle.

如果我们检查我们的答案的选择,only

follows this form.

The standard form of a circle is the following:

where r is the radius and (a, b) is the center. In order to rework what we have into this form, we have to complete the square.

Since

we need to find an a so that 2a=4.

．

For the y coordinate, we need to find the same thing except instead we have the equation 2b=6.

．

And then we have the coordinates of the circle's center:

The-intercept of the graph ofoccurs at the point at which- that is, at the point with coordinates．By definition,if, so we want to find this value. To do this, substitute accordingly:

Solve forby isolating it on the left; first, subtract 15:

Divide by 7:

The-intercept of the graph ofis at．

The-intercept of the graph of a function is the point at which it intersects the-axis. The-coordinate is 0, so the-coordinate can be found by evaluating．

The function is piecewise-defined, so it is necessary to use the definition applicable for．However, the first definition applies for values oflessthan 0, and the second, for valuesgreater．is undefined, and the graph ofhas no-intercept.

The-intercept of the graph of a function is the point at which it intersects the-axis. The-coordinate is 0, so the-coordinate can be found by solving the equation

This necessitates setting both definitions ofequal to 0 and solving for．For the first definition:

for

Add 16:

By the Square Root Property:

or

Since this definition holds only for, we only select．

For the second definition:

for

Add 25:

By the Square Root Property:

or

Since this definition holds only for, we only select．

Therefore, the graph has two-intercepts, which are atand．

The-intercept of the graph of a function is the point at which it intersects the-axis. The-coordinate is 0, so the-coordinate can be found by solving the equation

This necessitates setting both definitions ofequal to 0 and solving for．For the first definition:

for

However, this definition only holds for valuesless than0．No solution is yielded.

For the second definition:

for

However, this definition only holds for valuesgreater than or equal to0.No solution is yielded.

Therefore,has no solution, and the graph ofhas no-intercepts.

The-intercept of the graph of a function is the point at which it intersects the-axis. The-coordinate is 0, so the-coordinate can be found by evaluating．

The function is piecewise-defined, so it is necessary to use the definition applicable for．Since, andfor．这是定义使用.

The-intercept of the graph is the point．

If two distinct lines intersect at the point- that is, if both pass through this point - it follows thatis a solution of the equations of both. Therefore, setin both equations and determine whether they are true or not.

True -is a solution of this equation.

True -is a solution of this equation.

Therefore,is a solution of both equations, and the lines intersect at this point.

The graph of an inequality that includes either theorsymbol is the graph of the corresponding equation along with all of the points on either side of it. We are given both the line and the circle, so for each inequality, it remains to determine which side of each figure is included. In each case, this can be done by choosing any test point on either side of the figure, substituting its coordinates in the inequality, and determining whether the inequality is true or not. The easiest test point is．

This is true; select the side of this line that includes the origin.

This is true; select the side of this circle that includes the origin - the inside.

The solution sets of the individual inequalities are below:

The graph of the system is the intersection of the two sets, shown below:

The slope of a line determines its steepness.

Since slope is rise over run or

,

each of the slopes can be compared based on the ratio of rise to run.

A greater rise than run means a steeper line, or in our case, a hill. So for the "steepest" line, one must rise 5 units and move horizontally 1 unit.

Compare this with the linewhere one must rise one unit and move 8 units horizontally.