This code fills up the 6 member array with alternating Rectangle and Square objects. You can do this because the Square class is a subclass of Rectangle. That is, sinceSquares are Rectangles, you can store Square objects in Rectangle variables. However, even thoughrects[1]is a square, you CANNOT immediately reassign that to a Square object. The code has now come to consider all of the objects in the array as being Rectangle objects. You would need to explicitly type cast this to get the line to work:

Square s = (Square)(rects[1]);

The only error among the options given is the fact that this code assigns a new value to the variableval3, which is defined as a constant. (This is indicated by the keywordfinalbefore the rest of its declaration.) You cannot alter constants once they have been declared. Thus, the following line will cause a compile-time error:

val3 = val1 * 12;

The problematic line is this one:

int[] y = remove(x,4);

Notice that the variableyis defined as an array. Now, it is tempting to think (without looking too closely) that theremovemethod returns the array after the removal has been accomplished; however, this is not how the logic works in theremovemethod. Instead, it returns a boolean indicating whether or not this removal was successful or not (i.e. it tells you whether or not it actually found the value). Therefore, you cannot make an assignment like the one above, for the two types are not the same. That is,yis an integer array, whileremovereturns a boolean value!

When you implement an interface, all of the methods defined in that interface must be written in the class that is proposing to be such an implementation. (Or, if they are not implemented there, you need to involve abstract classes—but that is not our concern here.) The methods must match the prototypes proposed in the interface. In the example code,ServerInstancehas a methodwriteBytesthat returns a boolean value. However, theMyHostclass has implemented this method as returning abyte[]value. Since you cannot have different types of return values for methods with the same parameter set, Java interprets this as being the proposed implementation forwriteBytes(byte[] b), and this method must return a boolean ifMyHostis to implementServerInstance.

An error in compilation occurs before any code even attempts to execute. Thus, it is primarily a syntactical error in the code. In the selection above, the line

int x = 10; y = 21, z = 30;

has a semicolon right after10.This causes an error in the code directly following on this, for the code

y = 21, z = 30;

is not valid Java code.

There are other errors in this code.arr[i] =z/i;will cause a divide by 0 error wheniis 0. Also,arr[i] =z*i;will overrun the bounds of the arrayarr. However, these are not compile-time errors—i.e. errors that occur before the code is even able to run!

In this problem, Derived1 and Derived2 are children of the Base class. If we take a look at this line:

Base* bp = new Derived();

We are assigning a new Derived class to a base pointer. This will compile. Think of the Base as a larger object because it is the parent, so copying a smaller object into a larger one is acceptable.

Now let's look at this one:

Derived2* d2p = bp;

This line will cause the program to not compile. Since the Base class is considered the "bigger" object, copying a bigger object into a "smaller" one will result in a failure to copy everything over, this is known as aSlicing Problem.

We don't even have to look at the next line because we know that the program wil crash.

First we take a look at the given statement:

const int x = 10;

the const in front of "int" means that x will always hold the value of 10 and it will not change.

Let's observe all the choices.

int *p =&x

This line says to assign the address of x (in memory) to the pointer p. This however, will not compile because int * p is not marked as const. x is marked as a const so this forces int * p to be a const as well.

int * const q = &x

There is a const in this case but it is in the wrong place

const int * r = &x

The const is in the correct place and this is the correct answer

To understand this question, we have to understand what protected method means. A protected method is a method that is accessible to methods inside it's own class as well as it's children. This means that a protected method can be called in thechild class.

我们可以看到,内部主要()方法。This should already raise a red flag. A protected class is being called outside of the child class so it will not compile. Even those it's being calledonthe Base and Derived objects, the calls are not made inside Base and Derived class so neither line will compile.

In order to understand the error in this code, you must understand what the loop is doing. It is assigning variable types to the array ofObject基于对象的其余部分将loop control variableiby 4. You thus get a repeating pattern:

Integer, String, Double, String, Integer, String, Double, String, . . .

Now, index 8 will be an Integer (for it has a remainder of 0). This means that when you do the type cast to a String, you will receive a TypeCastException for the line reading:

Strings= (String)objects[8];

At this point of the code, it is not possible foraorbto be null. Furthermore, these arrays cannot contain null values, for they are made up of primitive types (inttypes). These cannot be set to null, as they are not objects. The potential error here is a little bit abstruse, but it is important to note. There is one possible error, namely that the 2D arrays are "ragged"; however we don't need to worry about this for the exam. Still, it is also possible that the arrayb(presuming that it is not null) is not the same size as the arraya.Since we are usingato set our loop counts, this could potentially mean that we overrun the arraybby using index values that are too large. (Note, it is also possible thatbcould be null, causing an error; however, there are no answer choices for that possibility.)