To solve this problem, we can use the power rule. That means we lower the exponent of the variable by one and multiply the variable by that original exponent.

We're going to treatas, as anything to the zero power is one.

Notice that, as anything times zero is zero.

First we need to find the derivative of the function.

Now, we can plug into the derivative function.

To find the derivative of the function, we use a combination of the quotient rule and product rule

To find the derivative of the function, we use the rule

and apply it to each term in the function

To find the derivative of the function, we use the quotient rule, which is

Applying this to the function from the problem statement, we get

To find the derivative of the function, we use the product rule, which by definition is

In this case, we can split up the product such that

This question requires us to understand two things.

First, the derivative ofis always, such that the exponent contains a single variable (any other operation or numerical factors could cause the chain rule to come into play; a later topic)

Second, we must understand the乘法法则衍生品. The product rule works as follows:

Understanding these two concepts allows us to tackle the derivative of the given function.

This simplifies to:

We are finished taking the derivative of the product!

There are two steps to this problem:

1) Take the first derivative of the function:

(applying the quotient rule)

(simplifying and combining terms)

因此,一阶导数如下:

2) Take the second derivative of the original function (or the first derivative of the first derivative we just found)

(applying the quotient rule)

(simplifying and combining terms)

Thus, our second derivative is as follows:

So the derivatives of the original function "r" should be:

We are given the function:

Applying thegeneral power rule, we can take the derivative

(3 e项删除,因为“e”是一个常数,and deriving a constant gives us zero!)

(further simplifying)

因此,我们的原始函数的导数the correct answer, is:

We are given the function:

The trick to making this function more approachable is to rewrite the function. The negative 1 on the right-most term allows us to rewrite the function as:

We can now apply thequotient rule for derivatives, and derive the function:

This derivative is quite messy, but we can simplify the numerator further!

Simplifying once more, we get our answer: