We start by rearranging the equation into the formy=mx+b(where m is the slope andbis theyintercept);y= 4x– 22
Now we know the slope is 4 and so the equation we are looking for must have them= 4 because the lines are parallel. We are also told that the equation must pass through the origin; this means that b = 0.

In 4x–y= 0 we can rearrange to gety= 4x. This fulfills both requirements.

The given equation is in standard form and needs to be converted to slope-intercept form which gives y = –2/5x + 6/5. The parallel line will have a slope of –2/5 (the same slope as the old line). The slope and the given point are substituted back into the slope-intercept form to yield y = –2/5x +5.

The slope of the given line isand a parallel line would have the same slope, so we need to find a line throughwith a slope of 2 by using the slope-intercept form of the equation for a line. The resulting line iswhich needs to be converted to the standard form to get.

Parallel lines have the same slope. Solve for the slope in the first line by converting the equation to slope-intercept form.

3x + 4y = 12

4y =–3x + 12

y =–(3/4)x + 3

slope =–3/4

We know that the second line will also have a slope of–3/4, and we are given the point (1,2). We can set up an equation in slope-intercept form and use these values to solve for the y-intercept.

y = mx + b

2 =–3/4(1) + b

2 =–3/4 + b

b = 2 + 3/4 = 2.75

Plug the y-intercept back into the equation to get our final answer.

y =–(3/4)x + 2.75

To solve, we will need to find the slope of the line. We know that it is parallel to the line given by the equation, meaning that the two lines will have equal slopes. Find the slope of the given line by converting the equation to slope-intercept form.

The slope of the line will be. In slope intercept-form, we know that the line will be. Now we can use the given point to find the y-intercept.

The final equation for the line will be.

Start by converting the original equation to slop-intercept form.

The slope of this line is. A parallel line will have the same slope. Now that we know the slope of our new line, we can use slope-intercept form and the given point to solve for the y-intercept.

Plug the y-intercept into the slope-intercept equation to get the final answer.

The line parallel tomust have a slope of,让我们the equation. To solve forb, we can substitute the values foryandx.

Therefore, the equation of the line is.

Converting the given line to slope-intercept form we get the following equation:

For parallel lines, the slopes must be equal, so the slope of the new line must also be. We can plug the new slope and the given point into the slope-intercept form to solve for the y-intercept of the new line.

Use the y-intercept in the slope-intercept equation to find the final answer.

Find the slope of the given line:(slope intercept form)

therefore the slope is

Parallel lines have the same slope, so now we need to find the equation of a line with slopeand going through pointby substituting values into the point-slope formula.

So,

Thus, the new equation is

Since the lines are parallel, the slopes must be the same. Therefore, (p+3) divided by (–2–5) must equal–2. 11 is the only choice that makes that equation true. This can be solved by setting up the equation and solving for p, or by plugging in the other answer choices for p.