If the largest of the three consecutive odd integers isd, then the three numbers are (in descending order):

d,d– 2,d– 4

This is true because consecutive odd integers always differ by two. Adding the three expressions together, we see that the sum is 3d– 6.

Sinceandmust be positive, eliminate choices with negative numbers or zero. Since they must be distinct (different), eliminate choices where. This leaves 4 and 5 (which is the only choice that does not add to 20), and the correct answer, 5 and 15.

Consecutive odd integers differ by 2. If the smallest integer is x, then

x + (x + 2) + (x + 4) = 93

3x + 6 = 93

3x = 87

x = 29

The three numbers are 29, 31, and 33, the largest of which is 33.

The odd/even status ofis not known, so no information can be determined about that of.

is known to be an integer, sois an even integer. Added to odd number, an odd sum is yielded; this is.

is known to be odd, sois also odd. Added to odd number, an even sum is yielded; this is.

is known to be even, sois even. Added to odd number; an odd sum is yielded; this is.

The numbers known to be odd areand; the number known to be even is; nothing is known about.

A power of an integer takes on the same odd/even status as that integer. Therefore, without knowing the odd/even status of, we do not know that of, and, subsequently, we cannot know that of. As a result, we cannot know the status of any of the other values of the other three variables in the subsequent statements. Therefore, none of the four choices are correct.

, the product of an even integer and another integer, is even. Therefore,is equal to the sum of an odd numberand an even number, and it is odd.

, the product of odd integers, is odd, so, the sum of odd integersand, is even.

, the product of an odd integer and an even integer, is even, so, the sum of an odd integerand even integer, is odd.

, the product of odd integers, is odd, so, the sum of odd integersand, is even.

The correct response is thatandare odd and thatandare even.

If exactly two of奇怪,那么到底七表达式之一being added is odd - namely, the only one that does not have an even factor (for example, ifandare odd, then the only odd number is). This makesthe sum of one odd number and six even number and, subsequently, odd.

If exactly three ofare odd, then exactly three of the seven expressions being added are odd - namely, the three that do not include the even factor (for example, if,, andare odd, then the three odd numbers are,, and). This makesthe sum of three odd numbers and four even numbers and, subsequently, odd.

If all four ofare odd, then all of the seven expressions being added, being the product of only odd numbers, are odd. This makesthe sum of seven odd numbers, and, subsequently, odd.

The correct choice is that all three scenarios are possible.

Add the ones digits:

Since there is no tens digit to carry over, proceed to add the tens digits:

The answer is.

If there are普通外nts taking Greek, then there areor普通外nts taking Latin. However, the question asks how many total students there are in the school, so you must add these two values together to get:

ortotal students.