Call Now to Set Up Tutoring:

(888) 888-0446

是EE Lower Level Math : How to find length of a line

Study concepts, example questions & explanations for ISEE Lower Level Math

Create An Account Create Tests & Flashcards

All ISEE Lower Level Math Resources

10 Diagnostic Tests 170 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #391 :Geometry

What is the distance between (2,5) and (-7, 17) ?

Possible Answers:

Correct answer:

Explanation:

的距离为mula is $d=\sqrt{(x_{2}-x_{1})^{2} + (y_{2}-y_{1})^{2}}$ .

Let $P_{1}=(-7,17)$ and $P_{2}=(2,5)$ :

$d=\sqrt{(2-(-7))^{2} + (5-17)^{2}}=\sqrt{(9)^{2} + (-12)^{2}}=\sqrt{81 + 144}=\sqrt{225}=15$

Report an Error

Example Question #2 :How To Find Length Of A Line

What is the distance between (-2, 3) and (4, -5) ?

Possible Answers:

Correct answer:

Explanation:

的距离为mula is given by $d=\sqrt{(x_{2}-x_{1})^{2} + (y_{2}-y_{1})^{2}}$ .

Let $P_{1}=(4,-5)$ and $P_{2}=(-2,3)$ :

$d=\sqrt{(-2-4)^{2} + (3-(-5)^{2}}=\sqrt{(-6)^{2} + (8)^{2}}=\sqrt{36 + 64}=\sqrt{100}=10$

Report an Error

Example Question #1 :How To Find Length Of A Line

What is the distance between (1,-3) and (13,-8) ?

Possible Answers:

Correct answer:

Explanation:

的距离为mula is given by $d=\sqrt{(x_{2}-x_{1})^{2} + (y_{2}-y_{1})^{2}}$ .

Let $P_{1}=(1,-3)$ and $P_{2}=(13,-8)$ :

$d=\sqrt{(13-1)^{2} + (-8-(-3)^{2}}=\sqrt{(12)^{2} + (-5)^{2}}=\sqrt{144 + 25}=\sqrt{169}=13$

Report an Error

Example Question #4 :How To Find Length Of A Line

What is the distance between the points (-2,1) and (10,-4) ?

Possible Answers:

Correct answer:

Explanation:

的距离为mula is $d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ .

Let $P_{1}= (-2, 1)$ and $P_{2}=(10, -4)$ .

Plug these two points into the distance formula:

$d = \sqrt{(10-(-2))^{2}+(-4-1)^{2}}=\sqrt{(12)^{2}+(-5)^{2}}=\sqrt{144+25}=\sqrt{169}=13$

Report an Error

Example Question #1331 :Isee Lower Level (Grades 5 6) Mathematics Achievement

If a line with a length of 5 starts at the point (1,1) , which of the following isNOTa possible end point?

Possible Answers:

(-3, 4)

(-3,5)

(5, -2)

(4, 5)

(-2, -3)

Correct answer:

(-3,5)

Explanation:

Let $P_{1}=(1,1)$ , and let $P_{2}$ be the end point we are looking for.

Recall the distance formula:

$d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

Squaring the distance formula gives $d^{2} = (x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}$ .

Plug $P_{1}=(1,1)$ this squared distance formula and solve for $P_{2}$ :

$25 = (x_{2}-1)^{2}+(y_{2}-1)^{2}$

Substitute each response into this equation to see which one is false. The only response that doesn't work is (-3, 5) .

Report an Error

Example Question #6 :How To Find Length Of A Line

What is the distance between (-2, 1) and (1,5) ?

Possible Answers:

Correct answer:

Explanation:

的距离为mula is $d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ .

Let $P_{1}= (-2, 1)$ and $P_{2}=(1, 5)$ .

Plug these points into the distance formula:

$d = \sqrt{(1-(-2))^{2}+(5-1)^{2}}=\sqrt{(3)^{2}+(4)^{2}}=\sqrt{9+16}=\sqrt{25}=5$

Report an Error

Example Question #7 :How To Find Length Of A Line

If a line that is 13 inches in length starts at the point (1,2) , which of the following isNOTa possible end point?

Possible Answers:

(6, 14)

(13, 7)

(3, 15)

(-4, -10)

(-11, -3)

Correct answer:

(3, 15)

Explanation:

的距离为mula is given by $d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ .

Square both sides:

$d^{2} = (x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}$

Now, let $P_{1}=(1,2)$ , and let $P_{2}$ be the end point we are looking for.

Plug $P_{1}=(1,2)$ into the squared distance formula and solve for $P_{2}$ :

$169 = (x_{2}-1)^{2}+(y_{2}-2)^{2}$

Alternatively, you can plug in the answer choices and see which point makes the above equation untrue. The point (3, 15) matches this description and is therefore the correct answer.

Report an Error

Example Question #8 :How To Find Length Of A Line

How long is a line segment on the number line if it goes fromto?

Possible Answers:

Correct answer:

Explanation:

To find the length of a line on the number line when one point is negative and the other is positive, you must the the distances of both from zero.isspaces from zero where is the other point is just. So the distance is 6+5=11 .

Report an Error

Example Question #9 :How To Find Length Of A Line

What is the distance between (2,5) and (-7, 17)?

Possible Answers:

Correct answer:

Explanation:

的距离为mula is $d=\sqrt{(x_{2}-x_{1})^{2} + (y_{2}-y_{1})^{2}}$ .

Let $P_{1}=(-7,17)$ and $P_{2}=(2,5)$ :

$d=\sqrt{(2-(-7))^{2} + (5-17)^{2}}=\sqrt{(9)^{2} + (-12)^{2}}=\sqrt{81 + 144}=\sqrt{225}=15$

Report an Error

View Tutors

Jeffrey
Certified Tutor

Brigham Young University-Provo, Bachelor of Science, Electrical Engineering. City University of Seattle, Master of Science, P...

View Tutors

奥马尔
Certified Tutor

Arizona State University, Bachelors, Civil Engineering.

View Tutors

Robert
Certified Tutor

CUNY Medgar Evers College, Bachelor of Science, Computer and Information Sciences, General.

All ISEE Lower Level Math Resources

10 Diagnostic Tests 170 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

ACT Tutors in Los Angeles,English Tutors in Dallas Fort Worth,Physics Tutors in Chicago,Math Tutors in Boston,GMAT Tutors in San Francisco-Bay Area,Math Tutors in Seattle,考试Tutors in Boston,Calculus Tutors in Dallas Fort Worth,Spanish Tutors in San Diego,Math Tutors in Miami

Popular Courses & Classes

考试Courses & Classes in Miami,GMAT Courses & Classes in Boston,是EE Courses & Classes in Miami,ACT Courses & Classes in Los Angeles,SSAT Courses & Classes in Denver,GMAT Courses & Classes in Miami,ACT Courses & Classes in Philadelphia,GMAT Courses & Classes in San Francisco-Bay Area,GRE Courses & Classes in Washington DC,SAT Courses & Classes in Atlanta

Popular Test Prep

MCAT Test Prep in Atlanta,SSAT Test Prep in San Francisco-Bay Area,GRE Test Prep in Atlanta,SAT Test Prep in Atlanta,ACT Test Prep in Los Angeles,考试Test Prep in Denver,ACT Test Prep in Philadelphia,GRE Test Prep in Los Angeles,SSAT Test Prep in Denver,GMAT Test Prep in San Francisco-Bay Area

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

请建议你将dama负责ges (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

*Full legal name

Company name

*Phone number

*Email address

Address

*Address1

Address2

*City

*State

*Zipcode

*Country

Complaint Details

*URL of copyrighted work (where your original material is located)

*Please describe the copyrighted work so that it may be easily identified

我是老板,或者是一个gent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

*Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

是EE Lower Level Math : How to find length of a line

Study concepts, example questions & explanations for ISEE Lower Level Math

All ISEE Lower Level Math Resources

Example Questions

Example Question #391 :Geometry

Example Question #2 :How To Find Length Of A Line

Example Question #1 :How To Find Length Of A Line

Example Question #4 :How To Find Length Of A Line

Example Question #1331 :Isee Lower Level (Grades 5 6) Mathematics Achievement

Example Question #6 :How To Find Length Of A Line

Example Question #7 :How To Find Length Of A Line

Example Question #8 :How To Find Length Of A Line

Example Question #9 :How To Find Length Of A Line

All ISEE Lower Level Math Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Find the Best Tutors

Email address:
Your name:

Email address:
Your name:
Feedback: