All GRE Math Resources
例子Questions
例子Question #114 :Coordinate Geometry
What is the slope of the line with equation 4x– 16y= 24?
1/4
–1/4
1/8
–1/8
1/2
1/4
The equation of a line is:
y=mx+b, wheremis the slope
4x– 16y= 24
–16y= –4x+ 24
y= (–4x)/(–16) + 24/(–16)
y= (1/4)x– 1.5
Slope = 1/4
例子Question #115 :Coordinate Geometry
What is the slope of a line which passes through coordinatesand?
Slope is found by dividing the difference in the-coordinates by the difference in the-coordinates.
例子Question #116 :Coordinate Geometry
What is the slope of the line represented by the equation?
To rearrange the equation into aformat, you want to isolate theso that it is the sole variable, without a coefficient, on one side of the equation.
First, addto both sides to get.
Then, divide both sides by 6 to get.
If you divide each part of the numerator by 6, you get. This is in aform, and theis equal to, which is reduced down tofor the correct answer.
例子Question #117 :Coordinate Geometry
What is the slope of the given linear equation?
2x + 4y = -7
1/2
-2
-7/2
-1/2
-1/2
We can convert the given equation into slope-intercept form, y=mx+b, where m is the slope. We get y = (-1/2)x + (-7/2)
例子Question #118 :Coordinate Geometry
What is the slope of the line:
First put the question in slope intercept form (y = mx + b):
–(1/6)y =–(14/3)x–7 =>
y = 6(14/3)x–7
y = 28x–7.
The slope is 28.
例子Question #119 :Coordinate Geometry
What is the slope of a line that passes though the coordinatesand?
The slope is equal to the difference between the y-coordinates divided by the difference between the x-coordinates.
Use the give points in this formula to calculate the slope.
例子Question #231 :Geometry
What is the slope of a line running through pointsand?
The slope is equal to the difference between the y-coordinates divided by the difference between the x-coordinates.
Use the give points in this formula to calculate the slope.
例子Question #1 :How To Find Out If A Point Is On A Line With An Equation
Find the point where the liney= .25(x– 20) + 12 crosses thex-axis.
(–28,0)
(12,0)
(0,0)
(–7,0)
(0,–28)
(–28,0)
When the line crosses thex-axis, they-coordinate is 0. Substitute 0 into the equation foryand solve forx.
.25(x– 20) + 12 = 0
.25x– 5 = –12
.25x= –7
x= –28
The answer is the point (–28,0).
例子Question #2 :How To Find Out If A Point Is On A Line With An Equation
On a coordinate plane, two lines are represented by the equationsand. These two lines intersect at point. What are the coordinates of point?
You can solve for thewithin these two equations by eliminating the. By doing this, you get.
Solve forto getand plugback into either equation to get the value ofas 1.
例子Question #3 :How To Find Out If A Point Is On A Line With An Equation
If the two lines represented byandintersect at point, what are the coordinates of point?
Solve forby setting the two equations equal to one another:
Pluggingback into either equation gives.
These are the coordinates for the intersection of the two lines.