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ACT Math : Exponents and Rational Numbers

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Example Questions

Example Question #861 :Algebra

Which real number satisfies $2^{n}\cdot 4=8^{2}$ ?

Possible Answers:

$1$

$4$

$2$

$0$

$3$

Correct answer:

$4$

Explanation:

Simplying the equation, we get $2^{n}\cdot 4=64$ .

This further simplifies to $2^{n}=16$ .

$n=4$ satisfies this equation. You could also use $\log _{2}16$ to determine that $2^{4}=16$ .

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Example Question #862 :Algebra

Find the value ofif $\frac{64}{27}=\left ( \frac{4}{3} \right )^{x}$

Possible Answers:

Correct answer:

Explanation:

When a fraction is raised to an exponent, both the numerator and denominator are raised to that exponent. Therefore, the equation can be rewritten as $\frac{64}{27}=\frac{4^{x}}{3^{x}}$ . From here we can proceed one of two ways. We can either solve x for $64=4^{x}$ or $27=3^{x}$ . Let's solve the first equation. We simply multiply 4 by itself until we reach a value of 64. $4^{1}=4$ , $4^{2}=4\cdot4=16$ , $4^{3}=4\cdot4\cdot4=64$ , and so on. Since $4^{3}=64$ , we know that x = 3.

We can repeat this process for the second equation to get $3^{3}=3\cdot3\cdot3= 27$ , confirming our previous answer. However, since the ACT is a timed test, it is best to only solve one of the equations and move on. Then, if you have time left once all of the questions have been answered, you can come back and double check your answer by solving the other equation.

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Example Question #863 :Algebra

If $\small f(x)=2\times x^{3}$ and $\small g(x)=x+2$ , what is $\small f(g(3))$ ?

Possible Answers:

125

250

Correct answer:

250

Explanation:

Start from the inside. $\small g(3)=3+2=5$ . Then, $\small f(5)=2\times 5^{3}=2\times 125=250$ .

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Example Question #864 :Algebra

Simplify by expressing each term in exponential form.

$\frac{\sqrt[3]{8x^{7}}}{\sqrt[4]{81x^2}}$

Possible Answers:

$\frac{2x^{\frac{7}{6}}}{3}$

$\frac{2x^{\frac{14}{3}}}{3}$

$\frac{2x^{\frac{7}{3}}}{3x^{\frac{1}{2}}}$

None of these are correct.

$\frac{2x^{\frac{11}{6}}}{3}$

Correct answer:

$\frac{2x^{\frac{11}{6}}}{3}$

Explanation:

The rule for exponential ratios is $a^{\frac{m}{n}} = \sqrt[n]{a^{m}}$ .

Using this, we can convert the numerator and denominator quickly.

$\frac{\sqrt[3]{8x^{7}}}{\sqrt[4]{81x^2}} = \frac{(8^{\frac{1}{3}})(x^{\frac{7}{3}})}{(81^{\frac{1}{4}})(x^{\frac{2}{4}})} = \frac{2x^{\frac{7}{3}}}{3x^{\frac{1}{2}}}$

The middle step in the coversion is important, as there is a big difference between $8^{\frac{1}{3}}$ and $8^{\frac{7}{3}}$ , and likewise for the denominator.

Next, we can further simplify by remembering that

$\frac{a^{m}}{a^{n}} = a^{m-n}$ .

Find the least common denominator and simplify:

$\frac{2x^{\frac{7}{3}}}{3x^{\frac{1}{2}}} = \frac{2x^{(\frac{7}{3}-\frac{1}{2})}}{3} = \frac{2x^{\frac{11}{6}}}{3}$

Thus,

$\frac{\sqrt[3]{8x^{7}}}{\sqrt[4]{81x^2}} = \frac{2x^{\frac{11}{6}}}{3}$

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Example Question #865 :Algebra

Often, solving a root equation is as simple as switching to exponential form.

Simplify into exponential form:

$\frac{\sqrt[3]{125}}{\sqrt[5]{125}}$

Possible Answers:

$125^{\frac{2}{15}}$

$25^{\frac{1}{5}}$

$625^{\frac{1}{3}}$

$\sqrt[15]{125^{2}}$

None of these are correct.

Correct answer:

$125^{\frac{2}{15}}$

Explanation:

The rule for exponential ratios is $a^{\frac{m}{n}} = \sqrt[n]{a^{m}}$ .

Using this, we can convert the numerator and denominator quickly.

$\frac{\sqrt[3]{125}}{\sqrt[5]{125}} = \frac{125^{\frac{1}{3}}}{125^{\frac{1}{5}}}$

Next, we can further simplify by remembering that

$\frac{a^{m}}{a^{n}} = a^{m-n}$ .

Find the least common denominator and simplify:

$\frac{125^{\frac{1}{3}}}{125^{\frac{1}{5}}} = 125^{\frac{5}{15}-\frac{3}{15}} = 125^{\frac{2}{15}}$

Thus, our answer is $125^{\frac{2}{15}}$ . (Remember, the problem asked for exponential form!)

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Example Question #866 :Algebra

Which of the following is a value ofthat satisfies $\log_m256 =4$ ?

Possible Answers:

Correct answer:

Explanation:

When you have a logarithm in the form

$y=\log_bx$ ,

it is equal to

b^y=x .

Using the information given, we can rewrite the given equation in the second form to get

m^4=256 .

Now solving forwe get the result.

4^4=256

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Example Question #867 :Algebra

Solve for:

$\log _{a}243 = 5$

Possible Answers:

Correct answer:

Explanation:

When you have a logarithm in the form

$\log _{b}x = y$ ,

it is equal to

b^y = x .

We can rewrite the given equation as

a^5 = 243

Solving for, we get

$\sqrt[5]{a^5} = \sqrt[5]{243}$

a = 3 .

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Example Question #868 :Algebra

Solve for:

$\log_{4}a = 5$

Possible Answers:

100,000

10,000

625

1024

Correct answer:

1024

Explanation:

When you have a logarithm in the form

$\log _{b}x = y$ ,

it is equal to

b^y = x .

We can rewrite the given equation as

4^5 = a

Solving for, we get

a = 1024 .

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Example Question #869 :Algebra

Converting exponents to rational numbers often allows for faster simplification of those numbers.

Which of the following isincorrect? Convert exponents to rational numbers.

Possible Answers:

$16^{\frac{1}{2}} = \sqrt[3]{8}$

$18^{\frac{2}{3}} = \sqrt[3]{18^2}$

$\sqrt[4]{625} = 25^{\frac{1}{2}}$

$42^{\frac{0}{3}} = \sqrt[5]{1^{30}}$

$\sqrt[5]{10^{10}} = 10^2$

Correct answer:

$16^{\frac{1}{2}} = \sqrt[3]{8}$

Explanation:

To identify which answer is incorrect we need to do each of the conversions.

First lets look at $\sqrt[4]{625} = 25^{\frac{1}{2}}$

$625^{\frac{1}{4}}=5$

$25^{\frac{1}{2}}=5$ .

Therefore this conversion is true.

Next lets look at $42^{\frac{0}{3}} = \sqrt[5]{1^{30}}$ . For this particular one we can recognize that anything raised to a zero power is just one therefore this conversion is true.

From here lets look at $16^{\frac{1}{2}} = \sqrt[3]{8}$

$16^{\frac{1}{2}} = \sqrt{16}$

$\sqrt{16} = 4$

$\sqrt[3]{8} = 2$

Thus

$\sqrt{16} \neq \sqrt[3]{8}$ . Therefore this is an incorrect conversion and thus our answer.

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Example Question #870 :Algebra

Sometimes, seeing rational numbers makes it easier to understand an equation.

Convert the following into a rational number or numbers:

$\frac{5^{\frac{1}{3}}\cdot 5^{\frac{4}{5}}}{5^{\frac{1}{15}}}$

Possible Answers:

$\sqrt[4]{5} - 5$

$\sqrt[5]{25}$

$\frac{\sqrt[3]{5}}{\sqrt[3]{15}}$

$\sqrt[15]{5^{16}}$

$5(\sqrt[5]{5})$

Correct answer:

$\sqrt[15]{5^{16}}$

Explanation:

The rule for converting exponents to rational numbers is: $a^{\frac{m}{n}} = \sqrt[n]{a^m}$ .

Even with this, it is easier to work the problem as far as we can with exponents, then switch to rational expression when we run out of room:

$\frac{5^{\frac{1}{3}}\cdot 5^{\frac{4}{5}}}{5^{\frac{1}{15}}} = \frac{5^{\frac{17}{15}}}{5^\frac{1}{15}} = 5^{\frac{17}{15}-\frac{1}{15}} = 5^{\frac{16}{15}}$

At last, we convert, and obtain $5^{\frac{16}{15}} = \sqrt[15]{5^{16}}$ .

Thus,

$\frac{5^{\frac{1}{3}}\cdot 5^{\frac{4}{5}}}{5^{\frac{1}{15}}} = \sqrt[15]{5^{16}}$ .

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ACT Math : Exponents and Rational Numbers

Study concepts, example questions & explanations for ACT Math

All ACT Math Resources

Example Questions

Example Question #861 :Algebra

Example Question #862 :Algebra

Example Question #863 :Algebra

Example Question #864 :Algebra

Example Question #865 :Algebra

Example Question #866 :Algebra

Example Question #867 :Algebra

Example Question #868 :Algebra

Example Question #869 :Algebra

Example Question #870 :Algebra

All ACT Math Resources

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