Call Now to Set Up Tutoring:

(888) 888-0446

SSAT Upper Level Math : Parallel Lines

Study concepts, example questions & explanations for SSAT Upper Level Math

Create An Account Create Tests & Flashcards

All SSAT Upper Level Math Resources

6 Diagnostic Tests 311 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

← Previous 1 2 3 4 5 6 Next →

Example Question #10 :Coordinate Geometry

If the line through the points (5, –3) and (–2,p) is parallel to the liney= –2x– 3, what is the value ofp?

Possible Answers:

–17

–10

Correct answer:

Explanation:

Since the lines are parallel, the slopes must be the same. Therefore, (p+3) divided by (–2–5) must equal–2. 11 is the only choice that makes that equation true. This can be solved by setting up the equation and solving for p, or by plugging in the other answer choices for p.

$\frac{p--3}{-2-5}=\frac{p+3}{-2-5}=-2$

$\frac{p+3}{-7}=-2$

$(\frac{p+3}{-7})-7=-2(-7)$

p+3=14

p=11

Report an Error

Example Question #11 :How To Find The Equation Of A Parallel Line

Find the equation of the line that goes through the point (-3, 1) and is parallel to the line with the equation y=2x-1 .

Possible Answers:

$y=-\frac{1}{2}x+7$

y=2x+7

y=2x-3

y=-2x+7

Correct answer:

y=2x+7

Explanation:

Because the two lines are parallel, we know that the slope of the line we need to find must also be.

We can then plug in the given point and the slope into the equation of a line to find the y-intercept.

1=2(-3)+b

-6+b=1

b=7

Now, we can write the equation of the line.

y=2x+7

Report an Error

Example Question #12 :How To Find The Equation Of A Parallel Line

Find the equation of the line that passes through the point (1, -2) and is parallel to the line with the equation $y=\frac{3}{2}x-1$ .

Possible Answers:

$y=\frac{3}{2}x-\frac{1}{2}$

$y=\frac{3}{2}x-\frac{7}{2}$

$y=-\frac{2}{3}x-\frac{7}{2}$

$y=\frac{3}{2}x+\frac{7}{2}$

Correct answer:

$y=\frac{3}{2}x-\frac{7}{2}$

Explanation:

Because the two lines are parallel, we know that the slope of the line we need to find must also be $\frac{3}{2}$ .

Now, we can plug in the point given by the question to find the y-intercept.

$-2=\frac{3}{2}(1)+b$

$b+\frac{3}{2}=-2$

$b=-\frac{7}{2}$

From this, we can write the following equation:

$y=\frac{3}{2}x-\frac{7}{2}$

Report an Error

Example Question #13 :How To Find The Equation Of A Parallel Line

Find the equation of the line that passes through the point (-2, -4) and is parallel to the line with the equation y=3x-2 .

Possible Answers:

$y=\frac{1}{3}x+2$

$y=-\frac{1}{3}x+2$

y=3x+2

y=-3x+2

Correct answer:

y=3x+2

Explanation:

Because the two lines are parallel, we know that the slope of the line we need to find must also be.

Next, plug in the point given by the question to find the y-intercept of the line.

-4=3(-2)+b

b-6=-4

b=2

Now, we know that the equation of the line must be y=3x+2 .

Report an Error

Example Question #14 :How To Find The Equation Of A Parallel Line

Find the equation of the line that passes through the point (1, 2) and is parallel to the line with the equation y=-2x-1 .

Possible Answers:

y=-2x+4

$y=\frac{1}{2}x+4$

y=-2x-4

y=2x-3

Correct answer:

y=-2x+4

Explanation:

Because the two lines are parallel, we know that the slope of the line we need to find must also be.

Next, plug in the point given by the question to find the y-intercept of the line.

2=-2(1)+b

b-2=2

b=4

Now, we know the equation of the line must be y=-2x+4 .

Report an Error

Example Question #15 :How To Find The Equation Of A Parallel Line

Find the equation of the line that passes through the point (-2, 5) and is parallel to the line with the equation y=-x-2 .

Possible Answers:

y=-x+6

y=x+3

y=-x+3

y=x-4

Correct answer:

y=-x+3

Explanation:

Because the two lines are parallel, we know that the slope of the line we need to find must also be.

Next, plug in the point given by the question to find the y-intercept of the line.

5=-1(-2)+b

b+2=5

b=3

Now, we can write the equation for the line: y=-x+3

Report an Error

Example Question #16 :How To Find The Equation Of A Parallel Line

Find the equation of the line that passes through the point (-2, 3) and is parallel to the line with the equation $y=\frac{1}{2}x-2$ .

Possible Answers:

y=2x-1

$y=\frac{1}{2}x-2$

y=-2x+4

$y=\frac{1}{2}x+4$

Correct answer:

$y=\frac{1}{2}x+4$

Explanation:

Because the two lines are parallel, we know that the slope of the line we need to find must also be $\frac{1}{2}$ .

Next, plug in the point given by the question to find the y-intercept of the line.

$3=\frac{1}{2}(-2)+b$

b-1=3

b=4

Now, we knwo the equation of the line must be $y=\frac{1}{2}x+4$ .

Report an Error

Example Question #17 :How To Find The Equation Of A Parallel Line

Find the equation of the line that passes through the point (2, 8) and is parallel to the line with the equation y=4x-1 .

Possible Answers:

$y=\frac{1}{4}x+2$

y=4x

y=4x-2

$y=-\frac{1}{4}x$

Correct answer:

y=4x

Explanation:

Because the two lines are parallel, we know that the slope of the line we need to find must also be.

Next, plug in the point given by the question to find the y-intercept of the line.

8=4(2)+b

b+8=8

b=0

Thus, the equation of the line must be y=8x .

Report an Error

Example Question #18 :How To Find The Equation Of A Parallel Line

Find the equation of the line that passes through the point (10, 2) and is parallel to the line with the equation $y=\frac{1}{5}x-2$ .

Possible Answers:

$y=\frac{1}{5}x$

y=5x-1

y=-5x+2

$y=\frac{1}{5}x-6$

Correct answer:

$y=\frac{1}{5}x$

Explanation:

Because the two lines are parallel, we know that the slope of the line we need to find must also be $\frac{1}{5}$ .

Next, plug in the point given by the question to find the y-intercept of the line.

$2=\frac{1}{5}(10)+b$

b+2=2

b=0

The equation of the line is $y=\frac{1}{5}x$ .

Report an Error

Example Question #19 :How To Find The Equation Of A Parallel Line

Find the equation of the line that passes through the point (3, 1) and is parallel to the line with the equation $y=\frac{1}{3}x-9$ .

Possible Answers:

y=-3x

$y=\frac{1}{3}x$

$y=\frac{1}{3}x+2$

$y=-\frac{1}{3}x$

Correct answer:

$y=\frac{1}{3}x$

Explanation:

Because the two lines are parallel, we know that the slope of the line we need to find must also be $\frac{1}{3}$ .

Next, plug in the point given by the question to find the y-intercept of the line.

$1=\frac{1}{3}(3)+b$

b+1=1

b=0

The equation of the line is $y=\frac{1}{3}x$ .

Report an Error

← Previous 1 2 3 4 5 6 Next →

View SSAT- Upper Level Tutors

Robin
Certified Tutor

University of Vermont, Burlington, Bachelor in Arts, Art Teacher Education. Art Students League, Master of Fine Arts, Arts, G...

View SSAT- Upper Level Tutors

Claire
Certified Tutor

Augustana College, Bachelor of Fine Arts, Music Teacher Education.

View SSAT- Upper Level Tutors

Sumita
Certified Tutor

Duke University, Bachelors, Chemistry. Barry University, Masters, Biomedical Sciences.

All SSAT Upper Level Math Resources

6 Diagnostic Tests 311 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

Chemistry Tutors in Dallas Fort Worth,SSAT Tutors in New York City,Algebra Tutors in Seattle,Computer Science Tutors in Atlanta,SAT Tutors in Los Angeles,ACT Tutors in Dallas Fort Worth,ISEE Tutors in Denver,Physics Tutors in Houston,ISEE Tutors in Dallas Fort Worth,Chemistry Tutors in Chicago

Popular Courses & Classes

ISEE Courses & Classes in Houston,GMAT Courses & Classes in Phoenix,SAT Courses & Classes in Denver,Spanish Courses & Classes in Phoenix,LSAT Courses & Classes in San Francisco-Bay Area,SSAT Courses & Classes in Phoenix,ISEE Courses & Classes in Philadelphia,LSAT Courses & Classes in Denver,LSAT Courses & Classes in Chicago,SSAT Courses & Classes in San Francisco-Bay Area

Popular Test Prep

SAT Test Prep in Washington DC,SAT Test Prep in Dallas Fort Worth,SAT Test Prep in Atlanta,GMAT Test Prep in Los Angeles,SAT Test Prep in Phoenix,LSAT Test Prep in San Diego,在圣弗朗西斯科海湾地区LSAT考试准备,LSAT Test Prep in Boston,GRE Test Prep in Washington DC,ACT Test Prep in Washington DC

DMCA Complaint

如果你认为可用的内容the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

请建议你将dama负责ges (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

*Full legal name

Company name

*Phone number

*Email address

Address

*Address1

Address2

*City

*State

*Zipcode

*Country

Complaint Details

*URL of copyrighted work (where your original material is located)

*Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

*Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

SSAT Upper Level Math : Parallel Lines

Study concepts, example questions & explanations for SSAT Upper Level Math

All SSAT Upper Level Math Resources

Example Questions

Example Question #10 :Coordinate Geometry

Example Question #11 :How To Find The Equation Of A Parallel Line

Example Question #12 :How To Find The Equation Of A Parallel Line

Example Question #13 :How To Find The Equation Of A Parallel Line

Example Question #14 :How To Find The Equation Of A Parallel Line

Example Question #15 :How To Find The Equation Of A Parallel Line

Example Question #16 :How To Find The Equation Of A Parallel Line

Example Question #17 :How To Find The Equation Of A Parallel Line

Example Question #18 :How To Find The Equation Of A Parallel Line

Example Question #19 :How To Find The Equation Of A Parallel Line

All SSAT Upper Level Math Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Find the Best Tutors

Email address:
Your name:
Feedback: