AP Physics 1 : Sound Waves

年代tudy concepts, example questions & explanations for AP Physics 1

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Example Questions

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Example Question #1161 :Ap Physics 1

Consider a 37cm long harp string with a fundamental frequency of 440Hz.

年代uppose the string is pressed down in such a way that only a 10cm length of string vibrates. What is the speed of the wave produced when the string is plucked in terms ofthe speed of the wave when all 37cm of the string vibrate?

Possible Answers:

Correct answer:

Explanation:

The speed of a wave is a property of the medium, it is not affected by the length of the string. The frequency may change, but the speed remains constant. There is no change in the speed.

Example Question #1162 :Ap Physics 1

Consider a 37cm long harp string with a fundamental frequency of 440Hz.

If only half of the string is allowed to vibrate, what frequency will be heard?

Possible Answers:

Correct answer:

Explanation:

年代ince the speed of the wave does not change based on the length of the string and we know it has a fundamental frequency of 440Hz, a string of half the length will vibrate at twice the frequency, 880Hz. This makes sense as it will sound higher in pitch. You can try this with a rubber band on a shoebox. Plucking it while placing your finger halfway along the band will result in a higher pitched sound.

Example Question #1163 :Ap Physics 1

Consider a 37cm long harp string with a fundamental frequency of 440Hz.

What is the wavelength of the second harmonic of the string?

Possible Answers:

Correct answer:

Explanation:

The wavelength of the second harmonic of a standing wave on a string is just the length of the string. For the second harmonic, an entire cycle occurs on the length of the string. Therefore, the wavelength of the second harmonic for this string is 37cm or 0.37m. The wavelength for the first harmonic, or fundamental, is twice the length of the string, as this is when one half a cycle occurs over the length of the string.

Example Question #1164 :Ap Physics 1

If the first harmonic of a string has frequency, what is the frequency of theharmonic of that string in terms of?

Possible Answers:

Correct answer:

Explanation:

谐波描述wavele之间的关系ngths and frequency on a string. A given string will have a wave speed associated with it. Given this wave speed, the harmonics are the frequencies at which half-wavelengths occur along the length of the string. For instance, the first harmonic is the frequency at which a half-wavelength occurs over the string. The second harmonic completes one wave over the string. The string is 1.5 times the wavelength of the third harmonic and so on. Therefore, theharmonic has a frequency of.

Example Question #1165 :Ap Physics 1

鉴于20 kj的能量冲击盘的窗口e over a period of 5s with dimensions 2.5m by 4m, what is the sound level in decibels?

Possible Answers:

Correct answer:

Explanation:

The formula for intensity,is:

Whereis power in watts andis the surface area. The surface areain our case is:

The powercan be given asor in our case:

年代olve for intensity.

The formula for sound levelis:

, whereis the intensity andis the threshold of hearing, which is

Example Question #1166 :Ap Physics 1

At a distance offrom a fan exertingof mechanical energy, estimate the sound level if the threshold of hearing is

Possible Answers:

Correct answer:

Explanation:

First we need to solve for intensity, given by:

, whereis power,is the distance from the source of the sound.

In our case,and, therefore

To solve for sound level, we do

, whereis the intensity andis the threshold of hearing.

In this problem,

, and

Example Question #1167 :Ap Physics 1

By what factor will the sound level in decibels change if the intensity is increased by a factor of?

Possible Answers:

声音勒vel will change by a factor of

声音勒vel will change by a factor of

声音勒vel will change by a factor of

声音勒vel will change by a factor of

Correct answer:

声音勒vel will change by a factor of

Explanation:

Recall that the formula for sound levelgiven in decibels is given by:

, whereis the intensity andis the threshold of hearing.

声音勒vel is proportional to intensity by:

If the intensity is increased by a factor of, sound level would increase by a factor of

Example Question #11 :年代ound Waves

A guitar player hits a wrong note. The note he's supposed to hit is, but he's sharp and the note turns out to be. Starting from rest, how fast (and in which direction) do you have to run until the note sounds correct to you?

Possible Answers:

away from the noise.

away from the noise.

away from the noise.

towards the noise.

towards the noise.

Correct answer:

away from the noise.

Explanation:

In order to find the velocity needed, we use the Doppler equation:

Whereis the speed of sound in air,is the velocity of the observer, andis the velocity of the source, which is zero in this case since the guitar player is not moving. Since the guitarist is sharp, your adjustment must decrease the perceived frequency by, which means we use the negative sign in the numerator of the Doppler equation. Plug in the given values into the equation and solve for.

Because we need the note to be the final note to be lower in frequency than the original frequency, we need to run away from it.

Example Question #12 :年代ound Waves

The speed of sounds is the fastest in which of the following media?

Possible Answers:

The speed of sound is constant in all media.

Glass

Vacuum

Water

Air

Correct answer:

Glass

Explanation:

The speed of sound is fastest in the least compressible media of the lowest density. Sound does not propagate in a vacuum. Air and water are compressible media, so sound does not travel as fast in these as it does in glass, an incompressible medium. In general, the speed of sound is greatest in solids, and within each phase, faster as density decreases.

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