Call Now to Set Up Tutoring:

(888) 888-0446

SSAT Upper Level Math : How to find x or y intercept

Study concepts, example questions & explanations for SSAT Upper Level Math

Create An Account Create Tests & Flashcards

All SSAT Upper Level Math Resources

6 Diagnostic Tests 311 Practice Tests Question of the Day Flashcards Learn by Concept

例子问uestions

← Previous 1 2 Next →

例子问uestion #1 :How To Find X Or Y Intercept

What is the-intercept of the graph of the function $f \left ( x\right ) = 2x^{2} - 7x + 5$ ?

Possible Answers:

$\left (0,-7 \right )$

$\left ( 0, -3 \frac{1}{2}\right )$

$\left (0,5 \right )$

$\left (0,0 \right )$

$\left (0,2 \right )$

Correct answer:

$\left (0,5 \right )$

Explanation:

The-intercept of the graph of a function is the point at which it intersects the-axis - that is, at which x = 0 . This point is $\left (0, f(0) \right )$ , so evaluate f(0) :

$f \left ( x\right ) = 2x^{2} - 7x + 5$

$f \left (0\right ) = 2 \cdot 0^{2} - 7 \cdot 0 + 5$

$f \left (0\right ) = 0- 0 + 5 = 5$

The-intercept is $\left (0,5 \right )$ .

Report an Error

例子问uestion #1 :X And Y Intercept

Give the-intercept, if there is one, of the graph of the equation

$y = \frac{1}{x^{2}+ x} + 3$

Possible Answers:

The graph has no-intercept.

(0,3)

(0,4)

(0,2)

$\left ( 0, \frac{3}{2}\right )$

Correct answer:

The graph has no-intercept.

Explanation:

The-intercept is the point at which the graph crosses the-axis; at this point, the-coordinate is 0, so substituteforin the equation:

$y = \frac{1}{x^{2}+ x} + 3$

$y = \frac{1}{0^{2}+0} + 3$

$y = \frac{1}{0} + 3$

However, since this expression has 0 in a denominator, it is of undefined value. This means that there is no value ofpaired with-coordinate 0, and, subsequently, the graph of the equation has no-intercept.

Report an Error

例子问uestion #2 :Use Similar Triangles To Show Equal Slopes: Ccss.Math.Content.8.Ee.B.6

Give the-intercept, if there is one, of the graph of the equation

$y = \frac{3}{\left | 3x-8\right |}$

Possible Answers:

$\left ( 0, \frac{3}{5}\right )$

$\left ( 0, -\frac{3}{8}\right )$

The graph has no-intercept.

$\left ( 0, \frac{3}{8}\right )$

$\left ( 0,- \frac{3}{5}\right )$

Correct answer:

$\left ( 0, \frac{3}{8}\right )$

Explanation:

The-intercept is the point at which the graph crosses the-axis; at this point, the-coordinate is 0, so substituteforin the equation:

$y = \frac{3}{\left | 3x-8\right |}$

$y = \frac{3}{\left | 3 \cdot 0 -8\right |}$

$y = \frac{3}{\left | 0 -8\right |}$

$y = \frac{3}{\left | -8\right |}$

$y = \frac{3}{ 8}$

The-intercept is $\left ( 0, \frac{3}{8}\right )$ .

Report an Error

例子问uestion #4 :How To Find X Or Y Intercept

Give the-intercept, if there is one, of the graph of the equation

$y = 3(x-2)^{2} + 4 (x-7)$ .

Possible Answers:

(0, -16)

(0, -42)

The graph does not have a-intercept.

(0, 8)

(0, -64)

Correct answer:

(0, -16)

Explanation:

The-intercept is the point at which the graph crosses the-axis; at this point, the-coordinate is 0, so substituteforin the equation:

$y = 3(x-2)^{2} + 4 (x-7)$

$y = 3(0-2)^{2} + 4 (0-7)$

$y = 3( -2)^{2} + 4 ( -7)$

$y = 3 \cdot 4 + 4 ( -7)$

y = 12+ 4 ( -7)

y = 12+ (-28)

y = -16

The-intercept is the point (0, -16) .

Report an Error

例子问uestion #5 :How To Find X Or Y Intercept

A line passes through (5, 2) and is perpendicular to the line of the equation 3x-4y = 17 . Give the-intercept of this line.

Possible Answers:

$\left ( -1\frac{3}{4}, 0\right )$

$\left (2 \frac{1}{3}, 0 \right )$

The line has no-intercept.

$\left ( 8\frac{2}{3}, 0\right )$

$\left (6 \frac{1}{2}, 0 \right )$

Correct answer:

$\left (6 \frac{1}{2}, 0 \right )$

Explanation:

First, find the slope of the second line 3x-4y = 17 by solving for作为follows:

3x-4y = 17

3x-4y +4y - 17 = 17+4y - 17

4y = 3x-17

$\frac{4y }{4}=\frac{ 3x-17 }{4}$

$y = \frac{3}{4}x- \frac{17}{4}$

The equation is now in the slope-intercept form y = mx+ b ; the slope of the second line is the-coefficient $m= \frac{3}{4}$ .

The first line, being perpendicular to the second, has as its slope the opposite of the reciprocal of $\frac{3}{4}$ , which is $m=- \frac{4}{3}$ .

Therefore, we are looking for a line through (5, 2) with slope $m=- \frac{4}{3}$ . Using point-slope form

$y - y_{1} = m(x -x_{1})$

with

$x _{1 } =5, y _{1 } = 2,m=- \frac{4}{3}$ ,

方程变得

$y - 2 =- \frac{4}{3}(x -5)$ .

To find the-intercept, substitute 0 forand solve for:

$0 - 2 =- \frac{4}{3}(x -5)$

$- 2 =- \frac{4}{3}x+ \frac{20}{3}$

$- 2- \frac{20}{3} =- \frac{4}{3}x+ \frac{20}{3} - \frac{20}{3}$

$- \frac{26}{3} =- \frac{4}{3}x$

$- \frac{3} {4}\cdot\left (- \frac{26}{3} \right )=- \frac{3} {4}\cdot \left (- \frac{4}{3}x \right )$

$x= \frac{26}{4} = \frac{13}{2} = 6\frac{1}{2}$

The-intercept is the point $\left (6 \frac{1}{2}, 0 \right )$ .

Report an Error

例子问uestion #1 :X And Y Intercept

A line passes through (5, 2) and is parallel to the line of the equation 3x-4y = 17 . Give the-intercept of this line.

Possible Answers:

$\left ( 8\frac{2}{3}, 0\right )$

$\left (6 \frac{1}{2}, 0 \right )$

$\left (2 \frac{1}{3}, 0 \right )$

$\left ( -1\frac{3}{4}, 0\right )$

The line has no-intercept.

Correct answer:

$\left (2 \frac{1}{3}, 0 \right )$

Explanation:

First, find the slope of the second line 3x-4y = 17 by solving for作为follows:

3x-4y = 17

3x-4y +4y - 17 = 17+4y - 17

4y = 3x-17

$\frac{4y }{4}=\frac{ 3x-17 }{4}$

$y = \frac{3}{4}x- \frac{17}{4}$

The equation is now in the slope-intercept form y = mx+ b ; the slope of the second line is the-coefficient $m= \frac{3}{4}$ .

The first line, being parallel to the second, has the same slope.

Therefore, we are looking for a line through (5, 2) with slope $m= \frac{3}{4}$ . Using point-slope form

$y - y_{1} = m(x -x_{1})$

with

$x _{1 } =5, y _{1 } = 2,m= \frac{3}{4}$ ,

方程变得

$y - 2 = \frac{3}{4}(x -5)$ .

To find the-intercept, substitute 0 forand solve for:

$0 - 2 = \frac{3}{4}(x -5)$

$- 2 = \frac{3}{4} x - \frac{15}{4}$

$- 2 + \frac{15}{4}= \frac{3}{4} x - \frac{15}{4} + \frac{15}{4}$

$\frac{3}{4} x = \frac{7}{4}$

$\frac{4} {3}\cdot \frac{3}{4} x =\frac{4} {3}\cdot \frac{7}{4}$

$x = \frac{7}{3} = 2\frac{1}{3}$

The-intercept is the point $\left (2 \frac{1}{3}, 0 \right )$ .

Report an Error

例子问uestion #7 :How To Find X Or Y Intercept

Give the-intercept of the line with slope $\frac{2}{5}$ that passes through point (5, 9) .

Possible Answers:

(0, -11)

$\left (0, -17 \frac{1}{2} \right )$

The line has no-intercept.

$\left (0, -27 \frac{1}{2} \right )$

(0, 7)

Correct answer:

(0, 7)

Explanation:

By the point-slope formula, this line has the equation

$y - y_{1} = m(x -x_{1})$

where

$x_{1} = 5, y_{1} = 9 ,m = \frac{2}{5}$

By substitution, the equation becomes

$y -9 = \frac{2}{5}(x -5)$

To find the-intercept, substitute 0 forand solve for:

$y -9 = \frac{2}{5}(0 -5)$

$y -9 = \frac{2}{5}( -5)$

y - 9 = -2

y = 7

The-intercept is the point (0, 7) .

Report an Error

例子问uestion #8 :How To Find X Or Y Intercept

Give the-intercept of the line that passes through points (-3, 4) and (2, -3) .

Possible Answers:

$\left (0, - 8 \frac{1}{5} \right )$

The line has no-intercept.

$\left (0, - \frac{1}{5} \right )$

$\left (0, - \frac{1}{7} \right )$

$\left (0, - 5\frac{6}{7} \right )$

Correct answer:

$\left (0, - \frac{1}{5} \right )$

Explanation:

First, find the slope of the line, using the slope formula

$m = \frac{y_{2} -y_{1}}{x_{2}-x_{1}}$

setting $x_{1} = -3, y_{1} = 4, x_{2} = 2, y_{2} = -3$ :

$m = \frac{-3 -4}{2-(-3)} = \frac{-7}{5} =- \frac{7}{5}$

By the point-slope formula, this line has the equation

$y - y_{1} = m(x -x_{1})$

where

$x_{1} = -3, y_{1} = 4, m = - \frac{7}{5}$ ; the line becomes

$y - 4 = - \frac{7}{5}(x -(-3))$

$y - 4 = - \frac{7}{5}(x +3)$

To find the-intercept, substitute 0 forand solve for:

$y - 4 = - \frac{7}{5}(0+3)$

$y - 4 = - \frac{7}{5}(3)$

$y - 4 = - \frac{21}{5}$

$y - 4+ 4 = - \frac{21}{5} + 4$

$y = - \frac{1}{5}$

The-intercept is $\left (0, - \frac{1}{5} \right )$ .

Report an Error

例子问uestion #9 :How To Find X Or Y Intercept

Give the-intercept of the line that passes through points (-3, 4) and (2, -3) .

Possible Answers:

$\left (- 5\frac{6}{7} , 0 \right )$

$\left (- \frac{1}{7} , 0 \right )$

$\text{The line has no } x\text{-intercept.}$

$\left ( - 8 \frac{1}{5},0 \right )$

$\left ( - \frac{1}{5},0 \right )$

Correct answer:

$\left (- \frac{1}{7} , 0 \right )$

Explanation:

First, find the slope of the line, using the slope formula

$m = \frac{y_{2} -y_{1}}{x_{2}-x_{1}}$

setting $x_{1} = -3, y_{1} = 4, x_{2} = 2, y_{2} = -3$ :

$m = \frac{-3 -4}{2-(-3)} = \frac{-7}{5} =- \frac{7}{5}$

By the point-slope formula, this line has the equation

$y - y_{1} = m(x -x_{1})$

where

$x_{1} = -3, y_{1} = 4, m = - \frac{7}{5}$ ; the line becomes

$y - 4 = - \frac{7}{5}(x -(-3))$

$y - 4 = - \frac{7}{5}(x +3)$

To find the-intercept, substitute 0 forand solve for:

$0 - 4 = - \frac{7}{5}(x +3)$

$- 4 = - \frac{7}{5} x - \frac{21}{5}$

$- 4+ \frac{21}{5} = - \frac{7}{5} x - \frac{21}{5}+ \frac{21}{5}$

$\frac{1}{5} = - \frac{7}{5} x$

$- \frac{5}{7} \cdot \frac{1}{5} = - \frac{5}{7}\left ( - \frac{7}{5} x \right )$

$- \frac{1}{7} =x$

The-intercept is $\left (- \frac{1}{7} , 0 \right )$ .

Report an Error

例子问uestion #1 :How To Find X Or Y Intercept

Give the-intercept of the line with slope $\frac{2}{5}$ that passes through point (5, 9) .

Possible Answers:

$\left ( -27 \frac{1}{2}, 0 \right )$

$\left ( -17 \frac{1}{2}, 0 \right )$

(-11, 0)

$\text{The line has no } x \text{-intercept.}$

(7, 0)

Correct answer:

$\left ( -17 \frac{1}{2}, 0 \right )$

Explanation:

By the point-slope formula, this line has the equation

$y - y_{1} = m(x -x_{1})$

where

$x_{1} = 5, y_{1} = 9 ,m = \frac{2}{5}$

By substitution, the equation becomes

$y -9 = \frac{2}{5}(x -5)$

To find the-intercept, substitute 0 forand solve for:

$0-9 = \frac{2}{5}(x -5)$

$-9 = \frac{2}{5}x -2$

$-9 +2= \frac{2}{5}x -2+2$

$-7 = \frac{2}{5}x$

$\frac{5}{2} \cdot \left (-7 \right ) = \frac{5}{2} \cdot \frac{2}{5}x$

$x = -\frac{35}{2} = -17 \frac{1}{2}$

The-intercept is $\left ( -17 \frac{1}{2}, 0 \right )$ .

Report an Error

← Previous 1 2 Next →

View SSAT- Upper Level Tutors

Justin
Certified Tutor

Boston College, Bachelor in Arts, Philosophy. Montclair State University, Master of Arts Teaching, Education.

View SSAT- Upper Level Tutors

Gregory
Certified Tutor

Pennsylvania State University-Main Campus, Bachelor of Science, Chemical Engineering. Carnegie Mellon University, Doctor of P...

View SSAT- Upper Level Tutors

Patrick
Certified Tutor

Yale University, Bachelor in Arts, English. University of Florida, Master of Arts, English Composition.

All SSAT Upper Level Math Resources

6 Diagnostic Tests 311 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

GRE Tutors in Dallas Fort Worth,ACT Tutors in San Diego,Statistics Tutors in Seattle,SAT Tutors in Seattle,MCAT Tutors in San Diego,LSAT Tutors in Chicago,GMAT Tutors in Atlanta,French Tutors in Philadelphia,Biology Tutors in Phoenix,ACT Tutors in Denver

Popular Courses & Classes

GMAT Courses & Classes in Philadelphia,Spanish Courses & Classes in Denver,ISEE Courses & Classes in Houston,SAT Courses & Classes in Phoenix,LSAT Courses & Classes in Boston,ISEE Courses & Classes in Boston,ACT Courses & Classes in Philadelphia,GRE Courses & Classes in Philadelphia,LSAT Courses & Classes in Houston,LSAT Courses & Classes in Washington DC

Popular Test Prep

SSAT Test Prep in Dallas Fort Worth,GRE Test Prep in Houston,LSAT Test Prep in San Francisco-Bay Area,ACT Test Prep in Atlanta,LSAT Test Prep in Houston,SAT Test Prep in San Diego,SAT Test Prep in Boston,SSAT Test Prep in Denver,ISEE Test Prep in San Francisco-Bay Area,ACT Test Prep in San Diego

DMCA Complaint

如果你认为可用的内容the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

请建议你将dama负责ges (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

*Full legal name

Company name

*Phone number

*Email address

Address

*Address1

Address2

*City

*State

*Zipcode

*Country

Complaint Details

*URL of copyrighted work (where your original material is located)

*Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

*Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

SSAT Upper Level Math : How to find x or y intercept

Study concepts, example questions & explanations for SSAT Upper Level Math

All SSAT Upper Level Math Resources

例子问uestions

例子问uestion #1 :How To Find X Or Y Intercept

例子问uestion #1 :X And Y Intercept

例子问uestion #2 :Use Similar Triangles To Show Equal Slopes: Ccss.Math.Content.8.Ee.B.6

例子问uestion #4 :How To Find X Or Y Intercept

例子问uestion #5 :How To Find X Or Y Intercept

例子问uestion #1 :X And Y Intercept

例子问uestion #7 :How To Find X Or Y Intercept

例子问uestion #8 :How To Find X Or Y Intercept

例子问uestion #9 :How To Find X Or Y Intercept

例子问uestion #1 :How To Find X Or Y Intercept

All SSAT Upper Level Math Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Find the Best Tutors

Email address:
Your name:
Feedback: