To find the degree of a polynomial we must find the largest exponent in the function.

The degree of the polynomialis 5, as the largest exponent ofis 5 in the second term.

When a polynomial has more than one variable, we need to find the degree by adding the exponents of each variable in each term.

has a degree of 4 (since both exponents add up to 4), so the polynomial has a degree of 4 as this term has the highest degree.

When a polynomial has more than one variable, we need to find the degree by adding the exponents of each variable in each term.

Even thoughhas a degree of 5, it is not the highest degree in the polynomial -

has a degree of 6 (with exponents 1, 2, and 3). Therefore, the degree of the polynomial is 6.

The degree is defined as the largest exponent in the polynomial. In this case, it is.

When an exponent with a power is raised to another power, the value of the power are multiplied.

When multiplying exponents you add the powers together

多项式的次数是由the highest power. In this problem the highest power is 8.

The degree of a polynomial is the largest exponent on one of its variables (for a single variable), or the largest sum of exponents on variables in a single term (for multiple variables).

Here, the term with the largest exponent is, so the degree of the whole polynomial is 6.

Set up an equation for the sentence: 15 – 3 = 2x and solve for x. X equals 6. If you plug in 6 for x in the expression 24/x, you get24/6 = 4. 4 is only choice greater than a.

Notice that - (a-b) = b-a, so statement I & III are true after substituting the expression. Substitute the expression for statement II gives ((a+b)/(a-b))((a+b)/(b-a))=((a+b)(b+a))/((-1)(a-b)(a-b))=-1 〖(a+b)〗²/〖(a-b)〗²=-((a+b)/(a-b))²= -(a♦b)²≠ (a♦b)²

The best way to solve this problem is to plug in an appropriate value fora.For example, plug-in 11 forabecause 11 divided by 7 will give us a remainder of 4.

Then 3a + 5, wherea= 11, gives us 38. Then 38 divided by 3 gives a remainder of 2.

The algebra method is as follows:

adivided by 7 gives us some positive integerb,with a remainder of 4.

Thus,

a/ 7 =b4/7

a/ 7 = (7b +4) / 7

a =(7b+ 4)

then 3a + 5 =3 (7b+ 4)+ 5

(3a+5)/3 = [3(7b+ 4)+ 5] / 3

= (7b+ 4)+ 5/3

The first half of this expression (7b+ 4)is a positive integer, but the second half of this expression (5/3) gives us a remainder of 2.