First we write out the equation we are given.H+ (2L+2W) = 360.H= 40 andL= 23

40 + (2(23) + 2W) = 360

40 + (46 + 2W) = 360

46 + 2W= 320

2W= 274

W= 137

Method 1:

Trial and error to find a combination of factors of 80 that differ by the same amount will eventually yield 2, 5, 8. The average is 5.

Method 2:

Three terms of an arithmetic sequence can be written as x, x+d, and x+2d. Multiply these together using the distributive property to find the volume and the following equation results:

x³+ 3dx²+ 2d²x - 80 = 0

Find an integer value of x that creates an integer solution for d. Try x=1 and we see the equation 1 + 3d + 2d²- 80 = 0 or 2d²+ 3d -79 = 0. The determinant of this quadratic is 641, which is not a perfect square. Therefore, d is not an integer when x=1.

Try x=2 and we see the equation 8 + 12d + 4d²- 80 = 0 or d²+ 3d - 18 = 0. This is easily factored to (d+6)(d-3)=0 so d=-6 or d=3. Since a negative value of d will result in negative dimensions of the prism, d must equal 3. Therefore, when substituting x=2 and d=3, the dimensions x, x+d, and x+2d become 2, 5, and 8. The average is 5.

Based on our prompt, we can say that the prism has dimensions that can be represented as:

Dim1: x

Dim2: 2 * Dim1 = 2x

Dim3: (1/4) * Dim2 = (1/4) * 2x = (1/2) * x

More directly stated, therefore, our dimensions are: x, 2x, and 0.5x. Therefore, the volume is x * 2x * 0.5x = 64, which simplifies to x³= 64. Solving for x, we find x = 4. Therefore, our dimensions are:

x = 4

2x = 8

0.5x = 2

Or: 2 x 4 x 8

Based on our prompt, we can say that the prism has dimensions that can be represented as:

Dim1: x

Dim2: 3 * Dim1 = 3x

Dim3: 5 * Dim1 = 5x

More directly stated, therefore, our dimensions are: x, 3x, and 5x. Therefore, the volume is x * 3x * 5x = 120, which simplifies to 15x³= 120 or x³= 8. Solving for x, we find x = 2. Therefore, our dimensions are:

x = 2

3x = 6

5x = 10

Or: 2 x 6 x 10

In order to figure out how many cubic centimeters can fit into the box, we need to figure out the volume of the box in terms of cubic centimeters. However, the measurements of the box are given in meters. Therefore, we need to convert these measurements to centimeters and then determine the volume of the box.

There are 100 centimeters in one meter. This means that in order to convert from meters to centimeters, we must multiply by 100.

The length of the box is 2 meters, which is equal to 2 x 100, or 200, centimeters.

The width of the box is 0.5(100) = 50 centimeters.

The height of the box is 3.2(100) = 320 centimeters.

Now that all of our measurements are in centimeters, we can calculate the volume of the box in cubic centimeters. Remember that the volume of a rectangular box (or prism) is equal to the product of the length, width, and height.

V = length x width x height

V = (200 cm)(50 cm)(320 cm) = 3,200,000 cm³

To rewrite this in scientific notation, we must move the decimal six places to the left.

V = 3.2 x 10⁶cm³

The answer is 3.2 x 10⁶．

Letlbe the length,wbe the width, andhbe the height of the prism. We are told that the length is twice the width, and that the width is twice the height. We can set up the following two equations:

l= 2w

w= 2h

接下来,我们被告知,表面积等于to 252 square units. Using the formula for the surface area of the rectangular prism, we can write the following equation:

surface area = 2lw+ 2lh+ 2wh= 252

We now have three equations and three unknowns. In order to solve for one of the variables, let's try to writewandlin terms ofh．We know thatw= 2h．Becausel= 2w, we can writelas follows:

l= 2w= 2(2h) = 4h

Now, let's substitutew= 2handl= 4hinto the equation we wrote for surface area.

2(4h)(2h) + 2(4h)(h) + 2(2h)(h) = 252

Simplify each term.

16h²+ 8h²+ 4h²= 252

Combineh²terms.

28h²= 252

Divide both sides by 28.

h²= 9

Take the square root of both sides.

h= 3.

This means thath= 3. Becausew= 2h, the width must be 6. And becausel= 2w, the length must be 12.

Because we now know the length, width, and height, we can find the volume of the prism, which is what the question ultimately requires us to find.

volume of a prism =l •w•h

volume = 12(6)(3)

= 216 cubic units

The answer is 216.

The volume of B is 7920 in³．The volume of A is 7722 in³．Treasure Chest B can hold more treasure.

The problem is simple, butbe careful．The units are not equal.First convert the last dimension into inches. There are 12 inches per foot. Therefore, the prism's dimensions really are: 4 in x 12 in x 24 in.

From this point, things are relatively easy. The distance from corner to corner in a three-dimensional prism like this can be found by using a variation on the Pythagorean Theorem that merely adds one dimension. That is,d²=x²+y²+z², ord=√(x²+y²+z²)

For our data, this would be:

d= √(4²+ 12²+ 24²) = √(16 + 144 + 576) = √(736) = √(2 * 2 * 2 * 2 * 2 * 23) = 4√(46)

First, let's represent our dimensions. We know the bottom could be represented as beingxbyx．The height is said to be three times one of these dimensions, so let's call it 3x．Based on this, we know the dimensions of the prism arex,x, and 3x．现在,对矩形棱柱的体积found by multiplying together its three dimensions. Therefore, if we know the overall volume is 375 in³, we can say:

375 =x*x* 3xor 375 = 3x³

Simplifying, we first divide by 3: 125 =x³．Taking the cube root of both sides, we find thatx= 5.

Now, be careful．The dimensionsare not5, 5, 5. They are (recall)x,x, and 3x．Ifx= 5, this means the dimensions are 5, 5, and 15.

At this point, things are beginning to progress to the end of the problem. The distance from corner to corner in a three-dimensional prism like this can be found by using a variation on the Pythagorean Theorem that merely adds one dimension. That is,d²=x²+y²+z², ord= √(x²+y²+z²)

For our data, this would be:d= √(5²+ 5²+ 15²) = √(25 + 25 + 225) = √(275) = √(5 * 5 * 11) = 5√(11) in