All Common Core: 7th Grade Math Resources
Example Questions
Example Question #51 :Grade 7
A baker can decorateof a wedding cake inof an hour. If the baker continues this rate, how much of the wedding cake can he decorate per hour?
The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have the portion of the cake decorated,, divided by hours,:
Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve.
Therefore:
The baker can decorateof the wedding cake per hour.
Example Question #52 :Grade 7
A painter can paintof a house inof an hour. If he continues this rate, how much of the house can he paint per hour?
The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have portion of the house painted,, divided by hours,:
Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve.
Therefore:
The painter can paintof a house per hour.
Example Question #53 :Grade 7
A painter can paintof a house inof an hour. If he continues this rate, how much of the house can he paint per hour?
The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have portion of the house painted,, divided by hours,:
Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve.
Therefore:
The painter can paintof a house per hour.
Example Question #54 :Grade 7
A painter can paintof a house inof an hour. If he continues this rate, how much of the house can he paint per hour?
The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have portion of the house painted,, divided by hours,:
Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve.
Therefore:
The painter can paintof a house per hour.
Example Question #55 :Grade 7
A painter can paintof a house inof an hour. If he continues this rate, how much of the house can he paint per hour?
The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have portion of the house painted,, divided by hours,:
Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve.
Therefore:
The painter can paintof a house per hour.
Example Question #56 :Grade 7
A painter can paintof a house inof an hour. If he continues this rate, how much of the house can he paint per hour?
The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have portion of the house painted,, divided by hours,:
Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve.
Therefore:
The painter can paintof a house per hour.
Example Question #57 :Grade 7
A landscaper can mowof a yard inof an hour. If he continues at this rate, how many yards can the landscaper mow per hour?
The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have yards,, divided by hours,:
Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve.
Therefore:
The landscaper can mowyards per hour.
Example Question #58 :Grade 7
A landscaper can mowof a yard inof an hour. If he continues at this rate, how many yards can the landscaper mow per hour?
The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have yards,, divided by hours,:
Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve.
Therefore:
The landscaper can mowyards per hour.
Example Question #59 :Grade 7
A landscaper can mowof a yard inof an hour. If he continues at this rate, how many yards can the landscaper mow per hour?
The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have yards,, divided by hours,:
Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve.
Therefore:
The landscaper can mowyards per hour.
Example Question #60 :Grade 7
A landscaper can mowof a yard inof an hour. If he continues at this rate, how many yards can the landscaper mow per hour?
The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have yards,, divided by hours,:
Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve.
Therefore:
The landscaper can mowyards per hour.