All Calculus 1 Resources
Example Questions
Example Question #181 :Constant Of Proportionality
The rate of change of the number of constant of proportionality calculus problems is proportional to the population. The population increased from 15 to 6750 between September and October. What is the constant of proportionality in months-1?
We're told that the rate of change of the population is proportional to the population itself, meaning that this problem deals with exponential growth/decay. The population can be modeled thusly:
Whereis an initial population value, andis the constant of proportionality.
Since the population increased from 15 to 6750 between September and October, we can solve for this constant of proportionality (it is useful to treat the months as their number in the calendar):
Example Question #182 :Constant Of Proportionality
What is the constant of proportionality ofbetweenand?
The constant of proportionality betweenandis given by the equation
In this problem,
Example Question #183 :Constant Of Proportionality
of force is required to stretch a spring. What is the constant of proportionality of the spring?
The relation between the force and stretch of a spring is
whereis force,is the spring constant, or proportionality of the spring, andis how far the spring is strectched.
For this problem
Example Question #181 :Constant Of Proportionality
What is the constant of proportionality of a circle with a diameter ofand a circumference of?
The relation between circumference and diameter is
whereis the circumference of a circle andis the diameter of the circle.
The constant of proportionality isfor all circles.
Example Question #1081 :Rate
The population of a town grows exponentially fromtoin. What is the population growth constant?
Exponential growth is modeled by the equation
whereis the final amount,是我nital amount,is the growth constant andis time.
In this problem,,and. Substituting these variables into the growth equation the solving forgives us
Example Question #1082 :Rate
Cobalt-60 has a half-life of. What is the decay constant of Cobalt-60?
The half-life of an isotope is the time it takes for half the isotope to disappear. Isotopes decay exponentially.
Exponential decay is also modeled by the equation
whereis the final amount,是我nital amount,is the growth constant andis time.
Since half the isotope has disappeared, the final amountis half the inital amount, or.
In this problem,.
Substituting these variables into the exponential equation and solving forgives us
Example Question #1083 :Rate
The number of cats double every. How many cats will there be afterif there arecats initially?
Exponential growth is modeled by the equation
whereis the final amount,是我nital amount,is the growth constant andis time.
After, the number of cats has doubled, or the final amountis double the inital amount, or.
In this problem,.
Substituting these variables into the exponential equation and solving forgives us
To find the number cats afteryear,,, and
Example Question #1084 :Rate
The number of students enrolled in college has increased byevery year since. Ifstudents enrolled in, how many student enrolled in?
The exponential growth is modeled by the equation
whereis the final amount,是我nital amount,is the growth rate andis time.
In this problem,,, and. Substituting these values into the equation gives us
Example Question #1085 :Rate
The number of CD players owned has decreased byannually since. Ifpeople owned CD players in, how many people owned CD players in?
The exponential growth is modeled by the equation
whereis the final amount,是我nital amount,is the growth rate andis time.
In this problem,and.because the rate is decreasing. Substituting these values into the equation gives us
Example Question #1086 :Rate
You depositinto your savings account. After, your account hasin it. What is the interest rate of this account if the account was untouched during the?
The exponential growth is modeled by the equation
whereis the final amount,是我nital amount,is the growth rate andis time.
In this problem,,and. Substituting these variables into the growth equation and solving for r gives us