AP Chemistry : Concentration and Units

Study concepts, example questions & explanations for AP Chemistry

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Example Questions

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Example Question #8 :Titrations

How much solid NaOH must be dissolved to make 740mL of a 0.32M solution?

Possible Answers:

12.8g

9.47 * 102g

The sodium hydroxide will boil off with the water

9.47g

4.26g

Correct answer:

9.47g

Explanation:

This problem can be solved by stoichiometry. Remember that 0.32M gives us the moles of NaOH per liter, and solve for the number of moles per 0.740L.

Example Question #9 :Titrations

Find the mass ofin 10L of water if it is a 2m solution.

Possible Answers:

Correct answer:

Explanation:

Molality is grams of solute per kilogram of solvent.

Water has a density of one gram per mililiter, so one liter of water equal to one kilogram. If we have a 2m solution, that means we have two moles ofper kilogram of water.

has a molecular weight of.

This gives usof.

Example Question #2 :Identifying Unknown Volume

A chemist has a bottle containing a 2M aqueous solution of hydrochloric acid. He needs to create a 50mL solution of hydrochloric acid that has a concentration of 0.5M. What is the volume of 2M hydrochloric acid that he should dilute in order to achieve the desired concentration?

Possible Answers:

Correct answer:

Explanation:

In order to dilute the concentrated acid, we need to find the amount of concentrated acid that will be diluted to 50mL of total solution. We can find the volume of concentrated acid necessary by setting the final volume and concentration equal to the initial concentration and unknown volume.

The initial concentration is 2M, the final concentration is 0.5M, and the final volume is 50mL

This means that 12.5mL of concentrated acid needs to be diluted to 50mL of solution. This will result in a solution with a concentration of 0.5M.

Example Question #21 :解决方案

A chemist wants to turn a 50.0mL solution ofinto asolution. How much water should she add?

Possible Answers:

Correct answer:

Explanation:

To solve this problem, we may use the following equation relating the molarity and volume of two solutions:

Recall:

Plug in known values and solve.

However, this is not the final answer. The whole volume of the second, 0.4M solution is 85mL. Thus the chemist needs to add 25mL of water to the original solution to obtain the desired concentration.

Example Question #22 :解决方案

In order to dilute a 1mL solution that is 0.01M so that the solution is diluted to, how many milliliters does this solution need to be diluted to?

Possible Answers:

Correct answer:

Explanation:

Use the dilution formula:

Rearranging this equation gives:

Plugging in the values gives:

Example Question #31 :解决方案

What concentration would you have prepared if you diluted 30mL of a 0.350M salt solution to 50mL?

Possible Answers:

Correct answer:

Explanation:

Use the dilution formula:

Rearranging this equation gives:

Plugging in the values gives:

Therefore, after diluting the solution to 50mL, the solution concentration would be lowered from 0.35M to 0.21M.

Example Question #32 :解决方案

How many moles are in a 0.010L solution with a concentration that is?

Possible Answers:

Correct answer:

Explanation:

By using the concentration as a conversion factor, the number of moles can calculated by multiplying the concentration by the number of liters.

Therefore, there areinof asolution.

Example Question #33 :解决方案

In order to prepare a needed solution for an experiment, 0.082 grams ofwas dissolved in water to give a 35mL solution. What is the molarity of this solution?

Possible Answers:

Correct answer:

Explanation:

In order to calculate the concentration, we must use molarity formula:

We must use the molecular weight of sodium chloride to calculate the moles of solute:

Therefore, the concentration in molarity of this solution is 0.040M.

Example Question #34 :解决方案

How many moles are in 1000mL solution with a concentration that is?

Possible Answers:

Correct answer:

Explanation:

By simply using the concentration as a conversion factor, the number of moles can be calculated by multiplying the concentration by the number of liters. Before calculating the number of moles, the number of milliliters must be converted to liters using the fact that.

Therefore, there areinof asolution.

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